Paradise Trinity Day

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Re: Paradise Trinity Day

Post by Amigoo » Tue Jun 01, 2021 3:57 pm

:sunflower: Re: "2(A=2)" design,
added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf

:scratch: If the area of each of the two largest circles = 2,
what is length of diagonal blue line in the center?

:? "Which blue line?"
Yes (since "center" is qualifier) ;)

Tip: Have Pi while you consider sqrt(2). :roll

Rod ... :bike: ...

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Re: Paradise Trinity Day

Post by Amigoo » Thu Jun 03, 2021 6:46 am

:sunflower: Re: "QQuadrangles of 2" design*
(Quadrangles of Quadrature with sqrt(2) nesting) 8)

Michelangelo was hired to paint the ceiling of the QQuadrangles of 2,
but was counseled to wait until the project was proven impossible. :?
He is still waiting ... apparently. ;)

:geek: Geometer's secret ...
The two sets of golden lines have length relationship. :hithere

Typically, only geometry nerds of Quadraturial persuasion
discover the relationship, permitting portal passage
and proving that they "think outside the box". :rambo:

:scratch: So, you're thinkin' outside the box?!
Where's sqrt(1) in this geometry :?:

:cheers: A Quiddle of Impossible
When sticks not stones evoke leg bones,
afore some sticks align on plate,
twas sqrt(1), thence sqrt(8).

:lol: "Why did the chicken cross the road?"
To take the Sqrt(2) Eggspress through the twilight
lest one-way transit require another dispensation. :o

* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
with adjoining: http://aitnaru.org/images/A_Quiddle.pdf

Rod :D

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Re: Paradise Trinity Day

Post by Amigoo » Sat Jun 05, 2021 12:34 pm

:sunflower: Re: "cLife Squared" design

Comprehending Quadrature is like opening your own Book of Life! 8)

:roll The final chapter is amazing! (when you write it)
and it's always being written (if that be your style
... and eternity preference). ;)

Rod ... :bike: ...

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Re: Paradise Trinity Day

Post by Amigoo » Mon Jun 14, 2021 11:11 pm

:sunflower: Re: "cLife Squared" design,
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf

:duh Geometry nerds of Quadraturial persuasion can be so exasperating!
You would think that Quadrature was all about geometric precision. :roll:
(two small lines were needed for sqrt(2) balance). 8)

:geek: Geometer's secret ...
Large scalene triangle is easily divided
into four similar scalene triangles. :roll

Rod :D

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Re: Paradise Trinity Day

Post by Amigoo » Sat Jun 19, 2021 4:07 am

:sunflower: Re: "cLife Entangled" design,
updated in: updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf

Before the Big Bang, pre-matter was already entangled!
... according to the Book of Eternal Life. :farao:

:hithere Only in Quadrature exists a dual-sided key ...
that unlocks the portal when the time is right. ;)

Quadrature tells the story of eternal partnership
... as symbolized by its dual-sided ringed key. 8)

:study: In the Book of Eternal Life,
there are many authors ... apparently.
Why not contribute a chapter?! ;)

Rod ... :bike: ...

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Re: Paradise Trinity Day

Post by Amigoo » Thu Jun 24, 2021 5:01 am

:study: Re: "Fermat's Last Theorem", by Simon Singh, 2011, p.51
"Pi = 4(1/1-1/3+1/5-1/7+1/9-1/11+1/13-1/15..)"

:sunflower: Apparently,
Pi = (1/1-1/3+1/5-1/7+1/9-1/11+1/13-1/15..)^2

Since 4/Pi
= 4/3.1415926535897932384626433832795..
= 1.2732395447351626861510701069801..
= (1.1283791670955125738961589031215..)^2
= (2/sqrt(Pi))^2

Restated,
4 = Pi x (1/1-1/3+1/5-1/7+1/9-1/11+1/13-1/15..)^2
4 = Pi x (2/sqrt(Pi))^2

:scratch: Who knew :?: :!:
Pi finally resolves with finite decimal digits. :roll:

Rod :)

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Re: Paradise Trinity Day

Post by Amigoo » Fri Jun 25, 2021 7:31 pm

:geek: Relationship of Circumference/2 to Diameter (C/2 : D)

3.1415926535897932384626433832795.. Pi
/ 2.0 = Pi/2

2.2214414690791831235079404950303.. (Pi(sqrt(2))/2
/ 1.4142135623730950488016887242097.. = Pi/2

1.5707963267948966192313216916398.. Pi/2
/ 1.0 = Pi/2

D = 1 x sqrt(2) x sqrt(2) = 2
C/2 = Pi/2 x sqrt(2) x sqrt(2) = Pi

8) Therefore, in all circles ...
Pi and sqrt(2) maintain fixed relationship :!:

Rod :stars:

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Re: Paradise Trinity Day

Post by Amigoo » Sat Jun 26, 2021 3:14 pm

:sunflower: Re: "Go Figure!" design*
A study of Pi as circumference of circle.

:scratch: Pop Quiz:
If Pi is the length of every red line,
what are the diameters of the 4 circles :?:

(geometry nerds of Quadraturial persuasion
usually ask next "What's the test ?!") :roll:

* added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf

Rod ... :bike: ...

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Re: Paradise Trinity Day

Post by Amigoo » Sun Jun 27, 2021 5:55 pm

:sunflower: Re: "Go Figure!" design
A study of Pi as circumference of circle.

:geek: Esoteric geometry that proves only that Pi remains
directly related to sqrt(2) regardless of circle's diameter.
Of what value is this?! Go figure! :roll:

Perhaps, sqrt(2) is transcendental or Pi is not. ;)

Rod :stars:

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Re: Paradise Trinity Day

Post by Amigoo » Mon Jun 28, 2021 12:48 am

:sunflower: Re: "Go Figure!" design
A study of Pi as circumference of circle.

:geek: Secret about "Three Moonsa P'eye":
Astrological phenomenon; occurs only when
sqrt(Pi) and sqrt(2) are in conjunction.

:idea: Regarding circle-squaring triangle:
2/sqrt(Pi) defines a circle (diameter)
and its Side of Circle's Square (SoCS).
And 2/sqrt(Pi) = sqrt(Pi)/(Pi/2). :roll

:scratch: "What about the short side?"
sqrt(4-Pi) re: Pythagorean Theorem ;)

Some believe Quadrature's "Three Moonsa P'eye"
heralds several near-term "Disclosure" events,
but others believe they're just relatives. :roll:
Go Figure! :)

Rod ... :bike: ...

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Re: Paradise Trinity Day

Post by Amigoo » Mon Jul 05, 2021 4:44 am

:sunflower: Re: "Go Figure!" design
Apparently, "Pi are square!" :roll:

:geek: Geometer's secrets ...
(Morbus Cyclometricus in deed!) ;)

Geometry nerds of Quadraturial persuasion know that
"Either sqrt(2) is transcendental or Pi is not!" refers to
the tandem geometric spirals of sqrt(Pi) and 2.

Regarding long side and hypotenuse of right triangle
in foundational pairing of sqrt(Pi) and 2, these lengths
increase by a precise factor of 8 in one 360 degree
extension of the two tandem spirals. 8)

2 / sqrt(Pi) = 8(2) / 8(sqrt(Pi))
= 1.1283791670955125738961589031215..

:sunflower: Re: "iiSpiral" design
(further exploration of "Go Figure!")

:geek: Transcendence of Pi renews every 360 degrees :!:
Don't believe it? Go Figure! :)

Rod :D

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Re: Paradise Trinity Day

Post by Amigoo » Sat Jul 10, 2021 2:22 pm

:sunflower: Re: "iQspiral" design

As a tee, no one needs to know that 'iQ' refers to Quadrature - not intelligence,
but it takes geometric IQ to comprehend how '8' relates to Quadrature :?
(serve square Pi to introduce the concept). :)

:geek: Geometer's secret iQ ...
A circle's square rests upon only eight points of the circle :!:

And it takes super geometric IQ to comprehend how Pi relates to "Sweet 16"
(smallest circle-squaring right triangle that begins the inner 360 degree spiral
has precisely 1/256 the area of the triangle beginning the outer spiral). 8)


:hithere Tasty Sqrt(2) Pi Sandwich (aka "Pi Corral")
for circle where diameter = 2

Perimeters of squares divided ...
8.0 / 5.6568542494923801952067548968388.. enclosing/inscribed
= 1.4142135623730950488016887242097.. sqrt(2)

Circumference vs perimeters (calc up & down) ...
= 8.0 enclosing perimeter
x 1.2732395447351626861510701069801.. (2/sqrt(Pi))^2
6.283185307179586476925286766559.. circumference = Pi(D)
/ 1.1107207345395915617539702475152.. (Pi/2)/sqrt(2)
= 5.6568542494923801952067548968388.. inscribed perimeter

Multiplier x divisor of calculated perimeters ...
1.2732395447351626861510701069801.. (2/sqrt(Pi))^2
x 1.1107207345395915617539702475152.. (Pi/2)/sqrt(2)
= 1.4142135623730950488016887242097.. sqrt(2)


:hithere Tasty Sqrt(2) Pi Sandwich, (aka "short stack") :roll:
for circle where diameter = 2 (calc up & down):

= 2.0 circle's diameter
x 1.2732395447351626861510701069801.. (2/sqrt(Pi))^2
1.5707963267948966192313216916398.. circumference/4
/ 1.1107207345395915617539702475152.. (Pi/2)/sqrt(2)
= 1.4142135623730950488016887242097.. side of inscribed square

1.2732395447351626861510701069801.. (2/sqrt(Pi))^2
x 1.1107207345395915617539702475152.. (Pi/2)/sqrt(2)
= 1.4142135623730950488016887242097.. sqrt(2)

8) Thus, Pi is directly associated with sqrt(2).
Go Figure! :)


Rod :D

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Re: Paradise Trinity Day

Post by Amigoo » Tue Jul 13, 2021 6:06 pm

:sunflower: Re: "de Triomphe" design*
(that's what they said) :scratch:
Go Figure! :)

:farao: A bit of enlightenment ...

The mystery dissolves a bit (for geometers of Quadraturial persuasion)
with esoteric presence of the right triangle's "Pi Fork" paired lines
(paired lines have either sqrt(Pi) or 2/sqrt(Pi) length relationship). 8)

:roll Today's Menu (a riddle)
Big Bang, Pi Fork, Oyster, Pearl
Bon Appétit :)

* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf

Rod ... :bike: ...

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Re: Paradise Trinity Day

Post by Amigoo » Sat Jul 17, 2021 3:14 pm

:sunflower: Re: "de Triomphe" design
(that's what they said) :scratch:

:geek: With area of smallest circle's square equal to 1/16 area
of largest circle's square (D = 2, A = Pi), there is no doubt ...
that Pi is evenly divisible by a sweet 16! :)

... and that Quadrature is impregnated with sqrt(2). :roll:

Rod :D

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Re: Paradise Trinity Day

Post by Amigoo » Sun Jul 18, 2021 11:13 am

:sunflower: Re: "TOI Box" design*

Within Quadrature's Triangles Of Interest box
one can assemble a collection of triangles to prove
"Once there was A point to Morbus Cyclometricus." 8)

Re: https://notes.misentropy.com/post/18903 ... ng-disease
"The ancient Greeks used the word τετραγωνιζειν (tetragonidzein),
which translates 'to occupy oneself with the quadrature'.

* added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf

Ro ... :bike: ...

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Re: Paradise Trinity Day

Post by Amigoo » Sun Jul 18, 2021 6:46 pm

:sunflower: Re: "TOI Box" design

:geek: Geometer's secret ...
The union of sqrt(Pi) and sqrt(2) is symbolized by a certain quadrilateral,
easily visible in the upper circle, with Pi and 2 being infinite eternals. 8)

The quadrilateral? Go Figure! :)

Rod :D

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Re: Paradise Trinity Day

Post by Amigoo » Mon Jul 19, 2021 3:14 am

:sunflower: Re: "TOI Box" design*

:scratch: Say what :?: :!:
There's a similar quadrilateral in the larger circle? :?
And its dimensions associate by sqrt(2) ?
Who told you ?! That cheeky Pi ? :roll:

* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf

:geek: Geometer's secret ...
In each quadrilateral, sqrt(2) length relationship exists
between the lines connecting their 90-degree angles. 8)

Ro ... :bike: ...

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Re: Paradise Trinity Day

Post by Amigoo » Tue Jul 20, 2021 2:21 pm

:sunflower: Re: "El Soluna" design
(from "el sol" + "la luna")

:geek: "Impossible" confluence of the circle-squaring
right and scalene triangles having sqrt(2) association
from their respective sqrt(2)-related circles. 8)

Rod :D

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Re: Paradise Trinity Day

Post by Amigoo » Thu Jul 22, 2021 4:44 am

:sunflower: Re: "GR Squared" design*
(Quadrature's Golden Ratio, squared)
* added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf

:geek: Featuring the identifying ratios ...

1.9130583802711007947403078280204.. sqrt(Pi) / sqrt(4-Pi)
1.1283791670955125738961589031215.. 2 / sqrt(Pi)
1.2732395447351626861510701069801.. (2 / sqrt(Pi)) ^2

Dimensions of largest inscribed right triangle ...

a = 1.7724538509055160272981674833411.. sqrt(Pi)
b = 0.92650275035220848584275966758914.. sqrt(4-Pi)
c = 2.0

:scratch: Pop Quiz ...
1. What are the line length ratios of the red diagonals?
2. When the Geiger counter triggers the switch that causes the flask to break,
is the testy cat of Quadraturial persuasion real or transcendental? or both? :?

:scratch: "What's the bib for ?!"
The next Pi eating contest! (of mathematical persuasion)

;) A Cartesian cat that has Morbus Cyclometricus
... might need a flee collar! :lol:

Ro ... :bike: ...

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Re: Paradise Trinity Day

Post by Amigoo » Sat Jul 24, 2021 3:22 am

:sunflower: Re: "PB & J" design,
added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf

:study: Long story short about "Pi + (4-Pi) = 4" ...

Locals knew that a nearby carpenter gifted baby Pythagoras
with random Blocks of wood for his playroom. Only later
did historians comprehend why Pythagoras favored three,
especially when they had precise Juxtaposition. However,

"PB&J" long remained a red herring since peanut butter
was not invented until 1895 by Dr. Kellogg (after 1882
when Ferdinand savored transcendental Pi). :roll

:geek: Geometer's secrets ...

The signature sandwich (hor d'oeuvre) at the annual Squared Circles Soirée
has one slice a right triangle and the other an isosceles right triangle
(similar to the red triangles in the center of this composition). 8)

Know one knows that baby Pythagoras observed from Quadrature
(know to him only as geometric shapes with unique juxtaposition)
that parallel universes would be the same but different. :?

Rod :D

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Re: Paradise Trinity Day

Post by Amigoo » Sun Jul 25, 2021 12:34 am

:sunflower: Re: "PB & J" design,
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf

:farao: In both universes, parallel, ...
Most people see a box and ask "whY" :?:
but geometry nerds of Quadraturial persuasion
(in both universes, parallel) see a box
and ask "X, Y, and Z" :?: :!:

Ro ... :bike: ...

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