Paradise Trinity Day

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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Pivot design
"Quadrature is a delicate balance of Pi."

:geek: If the circle can be squared ...
clues may exist in the Pythagorean Pivot
of sqrt(2)-related isosceles right triangles. :finger:

Rod ... :bike: ...
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Pivot design*
"Quadrature is a delicate balance of Pi."

* added to: http://aitnaru.org/images/Pi_Fork_n_Lute.pdf

Rod :D
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Pivot design
"Quadrature is a delicate balance of Pi."

:geek: Diameter was removed for composition clarity
that now highlights "delicate balance of Pi". :roll

:scratch: "Where's the diameter?" Surely you jest! :roll:

Rod ... :bike: ...
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Re: Paradise Trinity Day

Post by Amigoo »

Re: https://www.dailymail.co.uk/health/arti ... argue.html

"Calling people 'obese' is hurtful, claim top psychologists who say
the correct term is 'living with obesity' because the condition is NOT a choice"

:scratch: Somehow there's a disconnect in this perspective ...
since losing weight by exercise and better diet is a choice
... as many people prove every year. ;)

Rod :)
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design
"Quadraturial PMS"

:geek: Who can tell :?: :!:
(seems to explain the obesity disconnect) :roll:

Rod :stars:
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Re: Paradise Trinity Day

Post by Amigoo »

Re: http://board.1111angels.com/viewtopic.p ... 00#p203218
Q tip #3: Qubit computers will still not find the last digit of Pi ...
because the Pi model(s) itself is inherently transcendental (IMO).
And seems to hint that sqrt(2) is the necessary Pi Corral. ;)

Rod ... :bike: ...
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design

:geek: Geometer's secret: "Senter" is derived from "Sentient" and "Center",
suggesting that a circle squared knows that it is the controversial center
of Quadrature, long-proven "impossible". :roll:

And since "Qubit computers will still not find the last digit of Pi
because the Pi model(s) itself is inherently transcendental (IMO)." :shock:

Rod :)
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design

Speaking of sqrt(2) ... :roll:

:idea: In a CSCSC geometric construct where D = 1 and D = 2 via sqrt(2)
and SoCS = sqrt(Pi)/2 and sqrt(Pi), inner and outer diameters associate by 2,
suggesting that Pi itself must be divisible by 2 ... precisely :!:

And further suggesting that Transcendental/2 is a non-transcendental reality
... or that Pi has been mathematical "sleight of hand" for centuries. :shock:

:scratch: "Say what?!" Pi on your fork is real -
all other Pi is imaginary (theoretical). ;)

Rod :)
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design
" . " (period, end of sentence) ;)

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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design
Pi has been mathematical "sleight of hand" for centuries.
:geek: Regarding circle's inscribed square and non-transcendental sqrt(2):
1/4 of the circle's circumference (an arc) seems to be the necessary clue
that resolves why sqrt(2) should be transcendental or Pi not. :roll:

:scratch: "Say what?!" Arc! Arc! ;)

Rod :stars:
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design

NTS (re: D=2): Pi : 2 ~ Pi/2 : sqrt(2) ~ Pi/4 : 1

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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design
NTS (re: D=2): Pi : 2 ~ Pi/2 : sqrt(2) ~ Pi/4 : 1
:geek: Toward the Pythagorean Model of Pi ...

Divide circle's diameter by sqrt(2) x times, then multiply final value (a straight line)
times y to calculate Pythagorean-equivalent semi-circumference z, then Real Pi. :finger:

:idea: Obviously easy math (to astute geometers) since x, y, and z might be integers
and this method calculates a Pi value tuned to sqrt(2), obvious host of Quadrature. ;)

Rod :stars:
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design
Toward the Pythagorean Model of Pi ...
Sqrt(2) digression with halfsies :roll:

- 2.0
- 1.7071067811865475244008443621048..
- 1.4142135623730950488016887242097..
- 1.2071067811865475244008443621048..
- 1.0
- 0.8535533905932737622004221810524..
- 0.70710678118654752440084436210485..
- 0.60355339059327376220042218105241..
- 0.5
- 0.4267766952966368811002110905262..
- 0.35355339059327376220042218105242..
- 0.3017766952966368811002110905262..
- 0.25

Rod :stars:
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design
Toward the Pythagorean Model of Pi ...
Sqrt(2) digression with halfsies (grouped)

- 2.0
- 1.7071067811865475244008443621048..
- 1.4142135623730950488016887242097..
- 1.2071067811865475244008443621048..

- 1.0
- 0.85355339059327376220042218105243..
- 0.70710678118654752440084436210485..
- 0.60355339059327376220042218105243..

- 0.5
- 0.42677669529663688110021109052621..
- 0.35355339059327376220042218105242..
- 0.30177669529663688110021109052621..

- 0.25
- 0.21338834764831844055010554526311..
- 0.17677669529663688110021109052621..
- 0.15088834764831844055010554526311..

- 0.125

Rod :stars:
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Pythagorean Mirror Senter design
Toward the Pythagorean Model of Pi (PPi) ...
:duh Apparently, PPi must be evenly divisible by sqrt(2)
... or one of its increments/decrements. :roll:

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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quadrature! design*

GTSFI ... with overlapping CSC and lotsa sqrt(2). ;)

* added to: http://aitnaru.org/images/Pi_Fork_n_Lute.pdf

Rod :D
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quadrature! design

:geek: Speaking of CSC ...
this geometry proves that a circle's circumference
always has sqrt(2) relationship to its diameter:
D : C/2, D/2 : C/4, D/4 : C/8, D/8 : C/16

with the constant ratio: 1 / (Pi/2)
= 0.63661977236758134307553505349006..

Rod :stars:
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quadrature! GPS design

:geek: Who knew :?: :!:
Quadrature requires a Geometric Positioning Solution.
(note digression pattern of circumference arcs
in relation to division of circumference by 2) 8)

Rod :)
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quadrature! GPS design
circumference has sqrt(2) relationship to diameter:
D : C/2, D/2 : C/4, D/4 : C/8, D/8 : C/16
:geek: arcs of decreasing circumference
4/8 (.5), 3/8 (.375), 2/8 (.25), 1/8 (.125)

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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quadrature! GPS design

Who knew :?: :!: Quadrature speaks Spiral. 8)

:roll: "Spiral" is just a feature of the CSC geometric construct,
with GPS just conjecturing how sqrt(2) might attune to Pi. ;)

Rod :)
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quinale! design

Tip: "Qu" is for Quadrature. ;)

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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quinale! design

:geek: Geometers' secret ...

While the center "handle" originated as colorful, geometric balance,
it might allude to the curtain of "transcendental" Pi being opened. :hithere

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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quinale! design

:geek: Geometers' secret ...

The geometric busyness at the bottom of the design (same color as "Pi Fork")
was created while confirming the consistent line length ratios throughout:
2.0, sqrt(2), sqrt(Pi), 2/sqrt(Pi) 8)

Rod :D
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quinale! design
( http://aitnaru.org/images/Pi_Fork_n_Lute.pdf )

:geek: Geometer's secret ...
The unusal geometric construct of the "handle"
is an abstract 'Q' symbol for "Quadrature". 8)

Rod ... :bike: ...
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Re: Paradise Trinity Day

Post by Amigoo »

:sunflower: Re: Quinale! design

Still, centuries later (or millennia), geometers are asking:
"Which came first: the circle or the square?" :?

:idea: Quadraturially speaking, the answer is "Yes" ...
since the circle-squaring right triangle (foundation of "Pi Fork")
defines both the circle and its square where the long side length
equals Side of Circle's Square and hypotenuse is circle's diameter. 8)

In these Cartesian Neighborhoods, the line drawn first
effectively identifies which came first. :roll:

Rod :)
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