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Re: Paradise Trinity Day

Posted: Sun Mar 29, 2020 3:14 am
by Amigoo
:sunflower: Re: The PoiT design (pronounced "The Poet")
"The Pi of impossible Triangulation"

:geek: Juxtaposition of triangles with sqrt(2) ambience. 8)

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Sun Mar 29, 2020 3:14 pm
by Amigoo
:sunflower: Re: The PoiT design* (pronounced "The Poet")
"The Pi of 'impossible' Triangulation"

* now added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf

Rod :D

Re: Paradise Trinity Day

Posted: Mon Mar 30, 2020 6:22 pm
by Amigoo
:sunflower: Re: The PoiT design (pronounced "The Poet")
"The Pi of 'impossible' Triangulation"

:farao: The Poit forecasts that Quadrature reveals a chrysallis
... but what of universe significance will soon emerge :?: :!:

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Tue Mar 31, 2020 6:46 pm
by Amigoo
:sunflower: Re: The PoiT design (pronounced "The Poet")
"The Pi of 'impossible' Triangulation"

:geek: Geometer's secret ...

Small irregular pentagon (golden) has precisely 1/4 area of large irregular pentagon
and each similar side of large pentagon has twice the length of the small's side. 8)

Also, each pentagon has a similar collection of circle-squaring objects:
scalene triangles, right triangles, isosceles trapezoids. :roll

E = MC^2 (Extreme Morbus Cyclometricus Squared)

Rod :D

Re: Paradise Trinity Day

Posted: Wed Apr 01, 2020 2:22 pm
by Amigoo
:sunflower: Re: The PoiT design (pronounced "The Poet")
E = MC^2 (Extreme Morbus Cyclometricus Squared)

:geek: "Moons of Pi" embellishment and a familiar tune:
(myth records that these were Martin's original lyrics,
revealing a geometer's first love of Quadrature) :roll:

Re: https://www.youtube.com/watch?v=5Bt_uJvlKK8
"When the moon hits your eye like a big piece of Pi ..." :love

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Thu Apr 02, 2020 11:22 am
by Amigoo
:sunflower: Re: The PoiTT design (pronounced "The Poet Tee")
"The Pi of 'impossible' Triangulation Trapezoidal" :roll:

:geek: Focus on enclosing trapezoid and its 4 similar trapezoids inscribed. 8)

Rod :stars:

Re: Paradise Trinity Day

Posted: Thu Apr 02, 2020 12:06 pm
by Amigoo
:sunflower: Re: The PoiTT design* (pronounced "The Poet Tee")
"The Pi of 'impossible' Triangulation Trapezoidal" :roll:

:geek: Focus on enclosing trapezoid and its 4 similar trapezoids inscribed. 8)

:scratch: "Where's the fourth trapezoid?" Go figure! ;)

* added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Fri Apr 03, 2020 8:26 am
by Amigoo
:sunflower: Re: The PoiT design (pronounced "The Poet")
E = MC^2 (Extreme Morbus Cyclometricus Squared)

:geek: Salient numbers ...
(re: circumference, diameter/sqrt(2) progression)

2/sqrt(Pi) = sqrt(Pi)/(Pi/2) = 2(1/sqrt(Pi))
= 1.1283791670955125738961589031215..
^2 = 1.2732395447351626861510701069801..
= (2/sqrt(Pi))^2

2 = 2.0
sqrt(2) = 1.4142135623730950488016887242097..
1 = 1.0
sqrt(2)/2 = 0.70710678118654752440084436210485..

Pi/1 = 3.1415926535897932384626433832795..
Pi/2 = 1.5707963267948966192313216916398..
Pi/4 = 0.78539816339744830961566084581988..
Pi/8 = 0.39269908169872415480783042290994..

Pi/1 / 2 = 1.5707963267948966192313216916398..
Pi/2 / sqrt(2) = 1.1107207345395915617539702475152..
Pi/4 / 1 = 0.78539816339744830961566084581988..
Pi/8 / sqrt(2)/2 = 0.55536036726979578087698512375759..

2 / 1.5707963267948966192313216916398.. = (2/sqrt(Pi))^2
sqrt(2) / 1.1107207345395915617539702475152.. = (2/sqrt(Pi))^2)
1 / 0.78539816339744830961566084581988.. = (2/sqrt(Pi))^2
sqrt(2)/2 / 0.55536036726979578087698512375759.. = (2/sqrt(Pi))^2

Rod :stars:

Re: Paradise Trinity Day

Posted: Fri Apr 03, 2020 4:44 pm
by Amigoo
:sunflower: Re: The PoiT Ratios design
E = MC^2 (Extreme Morbus Cyclometricus Squared)

:geek: Ratios of sides of overlapping right triangles
(circle-squaring right triangle and isosceles rt)

Effective calculation of Ratio 1
2 / 1.7724538509055160272981674833411.. sqrt(Pi)
= 1.1283791670955125738961589031215.. 2/sqrt(Pi)

Effective calculation of Ratio 2
1.4142135623730950488016887242097.. sqrt(2)
x 1.7724538509055160272981674833411.. sqrt(Pi)
= 2.506628274631000502415765284811.. sqrt(2)sqrt(Pi)
/2 = 1.2533141373155002512078826424055.. (sqrt(2)sqrt(Pi))/2

Both ratios multiplied (= hyp/side of isosceles right triangle)

1.1283791670955125738961589031215.. 2/sqrt(Pi)
x 1.2533141373155002512078826424055.. (sqrt(2)sqrt(Pi))/2
= 1.4142135623730950488016887242096.. sqrt(2)

Rod :stars:

Re: Paradise Trinity Day

Posted: Fri Apr 03, 2020 6:37 pm
by Amigoo
:sunflower: Re: The PoiT Ratios design,
added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf

:geek: One more Poet of "impossible" Quadrature. :roll:

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Sat Apr 04, 2020 3:03 am
by Amigoo
:sunflower: Re: The PoiT Star design
(for the collection known as "Quadrature of PoiT") :roll:

:geek: Line length ratio of long to short golden lines in center of design
= line length ratio of long to short lines in circle-squaring right triangle
= sqrt(Pi) / sqrt(4-Pi) = 1.9130583802711007947403078280205.. 8)

Rod :D

Re: Paradise Trinity Day

Posted: Sun Apr 05, 2020 4:22 am
by Amigoo
:sunflower: Re: AESOP design (new concept)
"All Eyes Syndicate On Pi"

Cartesian Fable or Pythagorean Reality? :scratch:

Rod :)

Re: Paradise Trinity Day

Posted: Sun Apr 05, 2020 7:52 pm
by Amigoo
:sunflower: Re: AESOP design
"All Eyes Syndicate On Pi" ;)

:geek: When Quadrature depicts the geometric scream:
"Move over Vesica! - there's new Pi in the Neighborhood." :roll:

See also: https://en.wikipedia.org/wiki/The_Scream
"I sensed an infinite scream passing through nature"

Rod ... :bike: ... (screechin' in square circles)

Re: Paradise Trinity Day

Posted: Mon Apr 06, 2020 12:22 pm
by Amigoo
:sunflower: Re: AESOP design*
"All Eyes Syndicate On Pi" ;)

:geek: Pythagorean Quadrature for D = 2,
where Pi + (4-Pi) = 4 since a^2 + b^2 = c^2

* simplified in: http://aitnaru.org/images/Yin_Yang_Pi.pdf

Rod :D

Re: Paradise Trinity Day

Posted: Wed Apr 08, 2020 7:07 am
by Amigoo
:sunflower: Re: Peace of Pi design

Ultimately, in Pythagorean Quadrature,
the Fork is the memorable Peace of Pi. ;)

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Thu Apr 09, 2020 1:29 pm
by Amigoo
:sunflower: Re: Peace of Pi design
Ultimately, in Pythagorean Quadrature,
the Fork is the most memorable Peace of Pi.
:scratch: Non-geometers believe smaller utensil in this Cartesian Place Setting is salad fork,
but it's usually provided for petite bites of the square Pi or for sharing a taste.

Note: Napkins (isosceles right triangles) adjoin perfectly aligned Forks. ;)

Rod :D

Re: Paradise Trinity Day

Posted: Fri Apr 10, 2020 6:22 am
by Amigoo
:sunflower: Re: Squared Circles design

Just circles squared ... by a unique scalene triangle. ;)

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Fri Apr 10, 2020 4:16 pm
by Amigoo
:sunflower: Re: Squared Circles design

Is Pi/2 ... precisely ... "transcendental"? :scratch:
Is sqrt(2) in Quadrature "transcendental" :scratch:

Rod :stars:

Re: Paradise Trinity Day

Posted: Sat Apr 11, 2020 5:55 pm
by Amigoo
:sunflower: Re: Squared Circles design*

:geek: Who knew :?: :!:
Pi is directly related to sqrt(2):
For a circle with Diameter = 2, Circumference = Pi(D)
therefore C/2 = Pi and Pi/2 relates to D/sqrt(2). 8)

:scratch: "Say what?"
Both Diameter and Pi divide by 2, precisely ...
and remain mathematically tandem. ;)

:scratch: "Say what?"
Take a look from outside the box. :roll:

* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf

Rod :D

Re: Paradise Trinity Day

Posted: Mon Apr 13, 2020 7:57 pm
by Amigoo
:sunflower: Re: Squared Circles design
Pi is directly related to sqrt(2
:geek: Obviously (within the domain of Cartesian geometry),
sqrt(Pi) and sqrt(2) have similar mathematical properties.
That one should be transcendental and the other not
gives evidence of conceptual ledgerdemain. :roll:

Rod :stars:

Re: Paradise Trinity Day

Posted: Wed Apr 15, 2020 12:12 pm
by Amigoo
:sunflower: Re: Behind the 8 design
Behind the 8 ... may linger a 7
:geek: "Go for it!" (they say) ;)

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Sat Apr 18, 2020 7:11 am
by Amigoo
:sunflower: Re: Behind the 8 design
Behind the 8 ... may linger a 7
:geek: Persistently Proportional Pi
[columns: / sqrt(2), / 2, * sqrt(2) ] ;)

2 / Pi = 0.63661977236758134307553505349006..
sqrt(2) / (Pi/2) = 0.90031631615710606955519919100674..
1 / (Pi/4) = 1.2732395447351626861510701069801..
(sqrt(2)/2) / (Pi/8) = 1.8006326323142121391103983820135..
.5 / (Pi/16) = 2.5464790894703253723021402139602..

Rod :stars: ^2

Re: Paradise Trinity Day

Posted: Sat Apr 18, 2020 3:33 pm
by Amigoo
:sunflower: Re: Behind the 8 design
Behind the 8 ... may linger a 7
:geek: Persistently Proportional Pi
[columns: / sqrt(2), / 2, * sqrt(2), * sqrt(2) ] ;)

2 / Pi = 0.63661977236758134307553505349006..
sqrt(2) / (Pi/2) = 0.90031631615710606955519919100674.. sqrt(2)
1 / (Pi/4) = 1.2732395447351626861510701069801.. 2
(sqrt(2)/2) / (Pi/8) = 1.8006326323142121391103983820135.. 2(sqrt(2))
.5 / (Pi/16) = 2.5464790894703253723021402139602.. 4
(sqrt(2)/4) / (Pi/32) = 3.6012652646284242782207967640269.. 4(sqrt(2))
.25 / (Pi/64) = 5.0929581789406507446042804279207.. 8

:farao: Geometers' secret about PPP Table
(Diameter = 2, half of Circumference = Pi)

Table gives relationship of D to C/2
as D decreases by sqrt(2), C2 by 2 :roll:

Rod :D

Re: Paradise Trinity Day

Posted: Sun Apr 19, 2020 1:23 am
by Amigoo
:sunflower: Re: Behind the 8 design
Behind the 8 ... may linger a 7
:geek: ... or three. ;)

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Tue Apr 21, 2020 5:55 am
by Amigoo
:sunflower: Re: Behind the 8 design*
"Behind the 8 ... may linger a 7"

:geek: Geometer's secret ...
Only sqrt(2) knows the family secret of the diagonal dark blue line
in the lower right quadrant of this composition ... since all new lines
associated with this line were later removed for design simplification. :roll:

* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf

Rod :D