Page 158 of 186
					
				Re: Paradise Trinity Day
				Posted: Wed Nov 20, 2019 5:11 am
				by Amigoo
				
 Re: Mitosis CQ design
"geometrically telophasic w/CQ"

 Geometers' secret ...
Short side of circle-squaring right triangle in the 3 CSCSC circles
downsizes by sqrt(2) from the largest to the smallest circle.   
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Thu Nov 21, 2019 12:23 pm
				by Amigoo
				
 Re: Mitosis CQ design*
"geometrically telophasic w/CQ"

 Geometers' secret ...
Short side of circle-squaring right triangle in the 3 CSCSC circles
downsizes by sqrt(2) from the largest to the smallest circle. 

 Geometers' secret (astute geometers know this) ...
Center of Quadrature is a common point on the long side.
* updated in: 
http://aitnaru.org/images/Quinale!.pdf
Rod  ...  

  ...
 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Fri Nov 22, 2019 7:22 pm
				by Amigoo
				
 Re: Mitosis CQ design
"geometrically telophasic w/CQ"

 Geometer's conclusion ...
Having chased these circle-squaring geometric objects all over the Neighborhood
(for several weeks), the conclusion is obvious: Pi cannot exist without sqrt(2)   
 
 
 "As Above, So Below" (the math and the geometry must agree):
"Either sqrt(2) is transcendental or Pi is not"  Period! End of story!   
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Sat Nov 23, 2019 10:22 am
				by Amigoo
				
 Re: Mitosis CQ design
"geometrically telophasic w/CQ"

 Geometers' secret ...
Center of Quadrature includes 2 sets of opposite angles:
45 degrees and 135 degrees (90 + 270 = 360).   
 
(geometric "strong force" = 135/45 = 3)   
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Sat Nov 23, 2019 6:06 pm
				by Amigoo
				
 Re: Holometabolous design
Revealing 7th architectural type of life design in Quadrature 
 
... and the belated antithesis of morbus cyclometricus?   
  
... and evidence of constellation Q~Lepidoptera?    
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Tue Nov 26, 2019 3:39 pm
				by Amigoo
				
 Re: Holometabolous design,
updated in:  
http://aitnaru.org/images/Quinale!.pdf
Re: 
https://www.youtube.com/watch?v=e5hRPy-pDsY
There's so much Quadrature packed into this Cartesian composition that
"Holy Metabolous!" becomes another Batman exclamation!    
 
Rod  ...  

  ...
 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Wed Nov 27, 2019 8:22 pm
				by Amigoo
				
 Re: Holometabolous design
 

 Fascinating geometric construction, this circle-squaring scalene in the largest circle
with two overlapping right triangles on the left that pivot inward on their right angle,
creating a smaller circle-squaring scalene ... with the short sides of both scalenes
having obvious sqrt(2) line length relationship.   
 
"Holy Metabolous!"   
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Thu Nov 28, 2019 4:44 pm
				by Amigoo
				
 Re: Holometabolous design

 Speaking of "right triangles" and "pivot" ...
3 circle-squaring right triangles also pivot on their right angle, creating a sqrt(2) sibling 
where respective sides of each triangle have sqrt(2) relationship, and largest/smallest 
of the 3 triangles differ by 2.0, precisely! Thus, Pi is evenly divisible by 2.   
 
"Holy Metabolous!" 
Rod  

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Sat Nov 30, 2019 12:22 pm
				by Amigoo
				
 Re: Holometabolous design

 Regarding the direct relationship of Pi and 2.0, sqrt(Pi) and sqrt(2),
Salient Seams of Means 'n Extremes is a table of those numbers.   
    
"Holy Metabolous!" 
Rod   ...  

  ...
 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Sun Dec 01, 2019 11:39 am
				by Amigoo
				
 Re: Holometabolous design

 Now, the geometry is hinting that there are two centers 
 
"Holy Metabolous!" 
  
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Tue Dec 03, 2019 1:33 pm
				by Amigoo
				
 Re: Holometabolous design
"Holy Metabolous!" 
 

 Either '
77' is geometrically esoteric ...
or the number of times this design has changed!   
 
Rod   ...  

 ...
 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Tue Dec 03, 2019 2:28 pm
				by Amigoo
				
 Re: Holometabolous design,
updated in: 
http://aitnaru.org/images/Quinale!.pdf
 
 Geometers' secret ...
The tip of each adjoined "scalpel" identifies one of the geometric centers
with "scalpel" hinting the precision of this "impossible"  Quadrature.   
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Wed Dec 04, 2019 2:11 am
				by Amigoo
				
 Re: Holometabolous design
Relative numbers (line lengths) ...
 

   "Say what?!"  Go figure!   
 
1.4142135623730950488016887242097..   SoIS
1.2533141373155002512078826424055..   SoCS/SoIS
1.7724538509055160272981674833411..   SoCS
1.1283791670955125738961589031215..   Diam/SoCS
2.0  Diameter
1.2533141373155002512078826424055..   SoCS/SoIS
x 1.1283791670955125738961589031215..   Diam/SoCS
= 1.4142135623730950488016887242097..   Sqrt(2)
 

   "SoIS, SoCS, Diam?!"  Sides 'n Center   
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Wed Dec 04, 2019 3:46 pm
				by Amigoo
				
 Re: Holometabolous design
 

  Geometers'  secret ...
The largest circle's inscribed isosceles trapezoid
(two overlapping circle-squaring scalene triangles)
has a sqrt(2) sibling with a similar trapezoid.   
And that circle would have a sqrt(2) sibling.  
  
Rod  ...  

  ...
 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Fri Dec 06, 2019 2:11 pm
				by Amigoo
				
 Re: Holometabolous design

 Geometers' Neighborhood secret ...
The inner trapezoid (dark blue) has precisely  

  one-fourth the area
of the larger, enclosing trapezoid (proves with simple geometry).   
  
At least, "simple" for good geometers.   
 
 
 Who can tell 
  
 
This Cartesian Neighborhood design has enough stuff (geometric objects, etc.)
to be the foundation of a new geometry-teaching board game.   
  
 
 "Whatsit called?" 
How would I know 

  "Holy Metabolous!"   
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Sat Dec 07, 2019 4:43 am
				by Amigoo
				
 Re: Holometabolous design
Given concentric squares with areas = 4.0, Pi, 2.0
4 / 3.1415926535897932384626433832795..
= 1.2732395447351626861510701069801..
3.1415926535897932384626433832795..
/ 2.0 = 1.5707963267948966192313216916398..
1.2732395447351626861510701069801..   (2/sqrt(Pi))^2
x 1.5707963267948966192313216916398..  Pi/2
= 2.0
 

  Pi has a precise location between 4.0 and 2.0
... but is not "precisely between".   
  
Rod  ...  

  ...  (usually in a precise location 
... between Here and There)   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Sat Dec 07, 2019 12:21 pm
				by Amigoo
				
 Re: Peace of Pi design
The salient concentricity of Quadrature.   
 
Rod    

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Sun Dec 08, 2019 3:47 am
				by Amigoo
				
 Re: Peace of Pi design*
The salient concentricity of Quadrature.
 
 
  Geometers' secret ...
Side length of circle's square = sqrt(Pi)
Side length of inner square = 2/sqrt(Pi)
sqrt(Pi) / (2/sqrt(Pi)) = Pi/2, D = 2.0
1.7724538509055160272981674833411..   sqrt(Pi)
/ 1.1283791670955125738961589031215..   2/sqrt(Pi)
= 1.5707963267948966192313216916398..   Pi/2
* added to: 
http://aitnaru.org/images/Quinale!.pdf
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Sun Dec 08, 2019 10:29 pm
				by Amigoo
				
 Re: Peace of Pi design 
 

  Who knew 
  
   
There's a Dunkin on the ER Bridge!   
 
 
  Regarding the inner circle ...
Diam = 1.2732395447351626861510701069801..   (2/sqrt(Pi))^2
SoCs = 1.1283791670955125738961589031215..   2/sqrt(Pi)
Rod  ...  

  ... (prefer Cartesian Plain w/ "impossible" sprinkles)
 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Mon Dec 09, 2019 7:27 am
				by Amigoo
				
 Re: Peace of Pi design 
 

   Geometers' "impossible" secret ...  
 
2/sqrt(Pi) defines both the circle (Diameter) 
and its square (Side of Circle's Square, SoCS)
1.1283791670955125738961589031215..   2/sqrt(Pi), SoCS
^2 = 1.2732395447351626861510701069801..  Diameter
 

   And in the circle-squaring right triangle,
ratio of Diameter to Long Side = 2/sqrt(Pi)
1.2732395447351626861510701069801..   Diameter 
/ 1.1283791670955125738961589031215..   Long Side
= 1.1283791670955125738961589031215..   2/sqrt(Pi)
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Mon Dec 09, 2019 5:22 pm
				by Amigoo
				
 Re: Peace of Pi design
 

 Quadrature is like a box of round chocolates -
there's a Peace of Pi in every one!   
  
Rod  ...  

 ...  (shoppin' around the rounds ...
but usually get around or three)   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Tue Dec 10, 2019 7:27 am
				by Amigoo
				
 Re: Peace of Pi design
Quadrature is like a box of round chocolates -
there's a Peace of Pi in every one! 
 
   Regarding the circle-squaring right triangle ...
ACOS (SoCS/Diameter) = ACOS (sqrt(Pi)/2)
= ACOS ( (2/sqrt(Pi)) / (2/sqrt(Pi))^2 )
= ACOS (0.88622692545275801364908374167057..)
=  27.597112635690604451732204752339.. degrees 
27.597112635690604451732204752339..
+ 62.402887364309395548267795247661..
+ 90 = 180 degrees
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Tue Dec 10, 2019 2:56 pm
				by Amigoo
				
 Re: Peace of Pi design
... and its circle-squaring triangles   
 
Of "impossible" Quadrature,
geometer-believers are always asked "What's your angle?!"    
    

 Angles of the circle-squaring 
scalene triangle:
45.0 , 62.402887364309395548267795247661..
72.597112635690604451732204752339.. degrees

 Angles of the circle-squaring 
right triangle:
90.0 , 62.402887364309395548267795247661..
27.597112635690604451732204752339.. degrees
   

  Pop Quiz:
Having driven in a straight line but wish to return to your starting point,
how many turns are required if each turn is 179 degrees  
 
The geometry hints that distance traveled is important. 
Rod  ...  

 ...  (known to execute U-Turns)   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Tue Dec 10, 2019 3:57 pm
				by Amigoo
				
  Pop's Quiz:
Having driven in a straight line but wish to return to your starting point,
how many turns are required if each turn is 179 degrees 

The geometry hints that distance traveled is important. 
 

   Pop's Riddle:  Not all turns have to be all left or all right,
but the best turns will be alright if none are left.   
 
Rod   

 
			 
			
					
				Re: Paradise Trinity Day
				Posted: Wed Dec 11, 2019 3:33 am
				by Amigoo
				
 Re: Pi Fork 'n BC design*
"And that's the truth!"
aka "Wildly Outrageous 'n Esoteric!"  (WOE!)   
 
* added to: 
http://aitnaru.org/images/Quinale!.pdf
Rod  ...  

  ...