Paradise Trinity Day

[Amigoo]

Re: Simple iQ design

They say, in most Cartesian Neighborhoods ...
circle-squaring patterns can be recognized with a Simple iQ.

Rod ... ... (Been there! Done that!)

[Amigoo]

Re: Simple iQ design
(updated in: http://aitnaru.org/images/Khristos_Voskrese.pdf )

A few more lines were added ...
but clue or red herring? or neither? or both?
Are you sure

Rod

[Amigoo]

Re: Simple iQ design

Once identified, the building blocks of squared circles (especially, certain geometric objects and line length ratios)
firmly resist all attempts to discover new insight about this "impossible" Quadrature. Even a proposed "Picasso theme"
for a stained glass window in a new-era Frank Lloyd building was rejected because the geometry is too predictable.

Go figure! ( start with 2/sqrt(Pi) ; - )

Rod

[Amigoo]

Re: Simple iQ design

Obviously, sqrt(2) is the host of this Cartesian composition,
teasing with two lines of the inscribed square of that circle
with 1/4 area of the inscribed square of the largest circle
... not to mention that all 4 circles are squared.

Rod ... ...

[Amigoo]

Re: Simple iQ design ("final, final")

“... ad infinitum.”
(a free spirit mind maps a Simple iQ)

Rod (Been there! Done that!)

[Amigoo]

Re: Simple iQ design

Who knew? Design might allude to local universe's king's chair!
a contrast to: https://en.wikipedia.org/wiki/Cassiopei ... tellation)

Rod

[Amigoo]

Re: Simple iQ design (aka "Double iQ")

The commander of a later Roswell craft decided not to cruise nearby
lest it also crash and be identified as "advanced weather balloon".

Rod

[Amigoo]

Re: Simple iQ design (aka "Double iQ")

When the marriage of sqrt(Pi) and sqrt(2) was first celebrated,
an Oracle with a Double iQ was consulted to design a logo.
Its TMI interpretation always trails with "... ad infinitum."

Interestingly, "Double iQ" was also noted in the previous millennium:
"The commander's Double iQ persuaded that a later Roswell craft not cruise
nearby lest it also crash and be identified as 'alien weather balloon'".

Rod

[Amigoo]

Re: Simple iQ design (aka "Double iQ")

With a few more lines,
the design is both Double iQ and eEsoteric.

Rod ... ...

[Amigoo]

Re: Cartesian Squares Inscribed design (CSI)

This Cartesian Scene Investigation, simplified Quadrature,
contrasts two inscribed squares having sqrt(2) relationship
within their nested circles, also squared (by area).

Rod

[Amigoo]

Re: Cartesian Squares Inscribed design (CSI)

“Nesting, Nesting, 1, 2, 3 .. 7”
Can you hear me now?

Rod

[Amigoo]

Re: Cartesian Squares Inscribed design (CSI)

“Nesting, Nesting, 1, 2, 3 .. 7”
Can you hear me now

With day-after-day revision, the design represents all that's needed to say
about three circles squared in a compositon marked by sqrt(2) nesting.

Rod

[Amigoo]

Re: Cartesian Squares Inscribed design (CSI)
“Nesting, Nesting, 1, 2, 3, .. 7”

Extreme simplification of ...
three circles, nested and squared,
in a Cartesian composition hosted by sqrt(2).

"Say what?!" What

Rod ... ...

[Amigoo]

Re: Cartesian Squares Inscribed design (CSI)

Extreme simplification of three circles

If this continuing revision is "extreme simplification"
... I'll be an uncle's monkey.

This latest revision seemed necessary to identify
the 3 circle-squaring right triangles* (the '7' shapes).
Now, "seventy times and seven" comes to mind,
(also exaggerates the number of revisions).

* These sqrt(2)-related circles (one not shown) easily identify
by the 1,2,4 length relationships of their hypotenusii.

Rod ... ...

[Amigoo]

Re: Cartesian Squares Inscribed design (CSI)

Who knew

While '7' may be a metaphysical - even spiritual - number, it also reflects
long-lasting approximation of Pi: Archimedes of Syracuse in Sicily, about 200 BCE,
estimated Pi (the constant later named) to be 22/7 (or 3 1/7).

In this CSI geometry, '7' represents short side and hypotenuse of a circle-squaring
right triangle. That these '7' replicate in nested, sqrt(2)-hosted Cartesian Neighborhoods
"proves" that sqrt(2) limits Pi's transcendence (or sqrt(2) is also transcendental).

Rod

[Amigoo]

sqrt(2) limits Pi's transcendence (or sqrt(2) is also transcendental)

sqrt(Pi) x sqrt(2) = 2.506628274631000502415765284811..
sqrt(Pi) / sqrt(2) = 1.2533141373155002512078826424055..

2.506628274631000502415765284811..
/ 1.2533141373155002512078826424055....
= 2.00000000000000000000000000000 .. 0

Rod ... ...

[Amigoo]

Speaking of the ethereal '7' ...
Who knew In this local universe, Patterns Rule!

A numeric pattern identifies a Pi approximation closer than 355/113
(focus is on the decimal portion of Pi with +3.0 assumed):

Pi = 3.141592 6535897932384626433832795..
99115/700000 = 0.141592 85714285714285714285714286..
355/113 = 3.141592 9203539823008849557522124..

22/7 = 3.1428571428571428571428571428571..
21/7 = 3.0
1/7 = 0.14285714285714285714285714285714..

1000-9 = 991/7000 = 0.14157142857142857142857142857143..
10000-89 = 9911/70000 = 0.14158 571428571428571428571428571..
100000-889 = 99111/700000 = 0.14158714285714285714285714285714..
100000-887 = 99113/700000 = 0.14159
100000-886 = 99114/700000 = 0.14159142857142857142857142857143..
100000-885 = 99115/700000 = 0.14159285714285714285714285714286..

Rod

[Amigoo]

Speaking of the ethereal '7' ...
Who knew In this local universe, Patterns Rule!
(even closer while maintaining 70.. divisor)

A numeric pattern identifies a Pi approximation closer than 355/113
(focus is on the decimal portion of Pi with +3.0 assumed):

Pi = 3.1415926 535897932384626433832795..
10000000-88515 = 9911485/70000000 = 0.1415926 4285714285714285714285714..
355/113 = 3.1415929 203539823008849557522124..

22/7 = 3.1428571428571428571428571428571..
21/7 = 3.0
1/7 = 0.14285714285714285714285714285714..

1000-9 = 991/7000 = 0.14157142857142857142857142857143..
10000-89 = 9911/70000 = 0.14158 571428571428571428571428571..
100000-889 = 99111/700000 = 0.14158714285714285714285714285714..
100000-887 = 99113/700000 = 0.14159
100000-886 = 99114/700000 = 0.14159142857142857142857142857143..
10000000-88515 = 9911485/70000000 = 0.14159264285714285714285714285714..
100000-885 = 99115/700000 = 0.14159285714285714285714285714286..

What's the dividend/divisor that gets even closer to Pi?
(this pattern hints that an algorithm can be created;
go for 16 decimal digits!)

Rod

[Amigoo]

Speaking of the ethereal '7' ...
Who knew In this local universe, Patterns Rule!
(includes beginning of pattern = 99/700)

A numeric pattern identifies a Pi approximation closer than 355/113
(focus is on the decimal portion of Pi with +3.0 assumed):

Pi = 3.1415926 535897932384626433832795..
10000000-88515 = 9911485/70000000 = 0.1415926 4285714285714285714285714..
355/113 = 3.1415929 203539823008849557522124..

22/7 = 3.1428571428571428571428571428571..
21/7 = 3.0
1/7 = 0.14285714285714285714285714285714..

100-1 = 99/700 = 0.14142857142857142857142857142857..
1000-9 = 991/7000 = 0.14157142857142857142857142857143..
10000-89 = 9911/70000 = 0.14158 571428571428571428571428571..
100000-889 = 99111/700000 = 0.14158714285714285714285714285714..
100000-887 = 99113/700000 = 0.14159
100000-886 = 99114/700000 = 0.14159142857142857142857142857143..
10000000-88515 = 9911485/70000000 = 0.14159264285714285714285714285714..
100000-885 = 99115/700000 = 0.14159285714285714285714285714286..

What's the dividend/divisor that gets even closer to Pi?
(this pattern hints that an algorithm can be created;
go for 16 decimal digits!)

Rod

[Amigoo]

Speaking of the ethereal '7' ...
Who knew In this local universe, Patterns Rule!
(includes the real beginning of pattern = 9/70)

A numeric pattern identifies a Pi approximation closer than 355/113
(focus is on the decimal portion of Pi with +3.0 assumed):

Pi = 3.1415926 535897932384626433832795..
10000000-88515 = 9911485/70000000 = 0.1415926 4285714285714285714285714..
355/113 = 3.1415929 203539823008849557522124..

22/7 = 3.1428571428571428571428571428571..
21/7 = 3.0
1/7 = 0.14285714285714285714285714285714..

10-1 = 9/70 = 0.12857142857142857142857142857143
100-1 = 99/700 = 0.14142857142857142857142857142857..
1000-9 = 991/7000 = 0.14157142857142857142857142857143..
10000-89 = 9911/70000 = 0.14158 571428571428571428571428571..
100000-889 = 99111/700000 = 0.14158714285714285714285714285714..
100000-887 = 99113/700000 = 0.14159
100000-886 = 99114/700000 = 0.14159142857142857142857142857143..
10000000-88515 = 9911485/70000000 = 0.14159264285714285714285714285714..

100000-885 = 99115/700000 = 0.14159285714285714285714285714286..

What's the dividend/divisor that gets even closer to Pi?
(this pattern hints that an algorithm can be created;
go for 16 decimal digits!)

[Amigoo]

Speaking of the ethereal '7' ...
Who knew In this local universe, Patterns Rule!

The evidence for Notable Number Nerds, aka "mathematicians",
aka "Evidence for Notable Invention of Arithmetic Cipher (ENIAC)"
The pattern alignment: https://ufile.io/uz2tz

See also:
https://en.wikipedia.org/wiki/ENIAC
https://en.wikipedia.org/wiki/Cipher

Rod

[Amigoo]

Speaking of the ethereal '7' ... (one more pattern entry)
Who knew In this local universe, Patterns Rule!

The evidence for Notable Number Nerds, aka "mathematicians",
aka "Evidence for Notable Invention of Arithmetic Cipher (ENIAC)"
The pattern alignment: https://ufile.io/scdfq

Rod ... ...

[Amigoo]

Speaking of the ethereal '7' ... (another pattern entry)
Who knew In this local universe, Patterns Rule!

The evidence for Notable Number Nerds, aka "mathematicians",
aka "Evidence for Notable Invention of Arithmetic Cipher (ENIAC)"
The pattern alignment: https://ufile.io/haz88

Rod ... ... (let algorithm find more ...
even to last decimal digit of Pi)

[Amigoo]

Speaking of the ethereal '7' ... (final entry)
Who knew In this local universe, Patterns Rule!

The evidence for Notable Number Nerds, aka "mathematicians",
aka "Evidence for Notable Invention of Arithmetic Cipher (ENIAC)"
The latest pattern alignment: https://ufile.io/0s6p5

Rod ... ... (let algorithm find more ...
even to last decimal digit of Pi)

[Amigoo]

Who knew In this local universe, Patterns Rule!

Eleven decimal digits of Pi is a symbolic plateau!
The latest pattern alignment: https://ufile.io/xsaf9

Rod ("Been there! Done that!")