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Re: Paradise Trinity Day

Posted: Tue Aug 21, 2018 4:22 am
by Amigoo
:flower: Re: Scalenitweet design
(aka "Sweet Scalenity")

:cheers: No wonder squared circles are considered "impossible" :!:
The 3 corner-to-corner magenta lines (connect these points
of the overlapping scalene triangles) all have equal length,
proving geometric balance in this simple composition. :roll:

Rod :stars:

Re: Paradise Trinity Day

Posted: Tue Aug 21, 2018 1:23 pm
by Amigoo
:flower: Re: Scalenitweet design*
"Quietly messaging Sweet Scalenity" ;)

Slightly recolored to highlight festive assembly of circle-squaring objects:
right triangle, scalene triangle, isosceles trapezoid, unique quadrilateral
... with honorable mention to the similar Point-to-Pointers triad. :roll:

* updated in http://aitnaru.org/images/Khristos_Voskrese.pdf

Rod :D

Re: Paradise Trinity Day

Posted: Tue Aug 21, 2018 11:44 pm
by Amigoo
:flower: Re: Scalenitweet design
"Quietly messaging Sweet Scalenity" ;)

:colors: :bounce: :compress: Chirp! Chirp!
Geometers' secret: Squared circles have building blocks (objects)
that, once discovered, permit unending Cartesian complexity. 8)

And Pi/16? Who knew :?: :!: What's that :?: :!:

Rod :stars:

Re: Paradise Trinity Day

Posted: Wed Aug 22, 2018 3:44 am
by Amigoo
:flower: Re: Scalenitweet design
"Quietly messaging Sweet Scalenity" ;)

:geek: Geometers' secret:

Similar objects that share one side and hypotenuse (respectively)
of an isosceles right triangle have line lengths with sqrt(2) relationship
regardless of the number of lines/angles in each object. In other words,
sqrt(2) defines all paired lines/angles from the two objects. 8)

:idea: Conversely, the objects are similar if this sqrt2) relationship
exists for all paired lines/angles from the two objects. ;)

Rod ... :bike: ... (prefer a slice of Pi cut on the hypotenuse)

Re: Paradise Trinity Day

Posted: Wed Aug 22, 2018 11:39 am
by Amigoo
:flower: Re: Scalenitweet design
"Quietly messaging Sweet Scalenity" ;)

:geek: Geometers' dark blue secret:
Vesica Piscis is present at this Squared Circles Soirée. 8)

Rod :D

Re: Paradise Trinity Day

Posted: Thu Aug 23, 2018 6:22 am
by Amigoo
:flower: Re: Scalenitweet design
"Quietly messaging Sweet Scalenity" ;)

At this Squared Circles Soirée, Vesica reveals
that Pi is evenly divisible by sqrt(2) 8)
... and therefore 2.0 :roll

:geek: Considering that (re: https://en.wikipedia.org/wiki/Transcendental_number )

"the square root of 2 is irrational but not a transcendental number,
since it is a solution of the polynomial equation x2 − 2 = 0" ...
and sqrt(2) is represented by an isosceles right triangle ...

... and that Pi can also be represented by a similar triangle,
then Pi's transcendental quality must devolve to sqrt(2) :shock:
at least, in these Cartesian Neighborhoods.

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Thu Aug 23, 2018 3:21 pm
by Amigoo
:flower: Re: Scalenitweet design
"Quietly messaging Sweet Scalenity" ;)
Pi is evenly divisible by sqrt(2)
:geek: Several straight lines were added to support
when sqrt(2) teases squared circle geometers ...
"Can you hear me now :?: :!: "

Rod :D

Re: Paradise Trinity Day

Posted: Thu Aug 23, 2018 10:33 pm
by Amigoo
:idea: For your next Squared Circles Soirée ...
decorate with Pi's distant relatives:

2.0 / sqrt(Pi) = sqrt(Pi) / (Pi/2)
= 1.1283791670955125738961589031215..

sqrt(Pi) x 1.1283791670955125738961589031215.. = 2.0
sqrt(Pi) / 1.1283791670955125738961589031215.. = Pi/2

2.0 / (Pi/2) = 1.2732395447351626861510701069801..
sqrt(1.2732395447351626861510701069801..)
= 1.1283791670955125738961589031215..

Rod :stars:

Re: Paradise Trinity Day

Posted: Fri Aug 24, 2018 8:46 pm
by Amigoo
:flower: Re: Scalenitwixt design

A new name was required but still related to "Scalenitweet"
... and considering that the geometric influence of sqrt(2)
seems betwixt and between the scalene triangles.

Besides, 'X' marks the spot(s). :roll:

Rod :D

Re: Paradise Trinity Day

Posted: Fri Aug 24, 2018 10:44 pm
by Amigoo
:flower: Re: Scalenitwixt design

Betwixt and between juxtapositional scalene,
quadrature reigns, sans king and sans queen.
Princess and prince, oft yonder, draw nigh -
irrational square roots of 2 and of Pi. ;)

Rod :)

Re: Paradise Trinity Day

Posted: Sat Aug 25, 2018 1:44 am
by Amigoo
:flower: Re: Scalenitwixt design

Ask not "What's inside the box?"
ask "What's not inside the box?" ;)

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Sat Aug 25, 2018 6:11 pm
by Amigoo
:flower: Re: Scalenitwixt design
ask "What's not inside the box?"

:geek: Given: SoCS = Side of Circle's Square,
2/sqrt(Pi) = 1.1283791670955125738961589031215..

If Diameter = 2/sqrt(Pi), SoCS = 1 (aka "Pi = 1")

:stars: Calculation: Area = Pi x radius^2
D = 1.1283791670955125738961589031215..
/ 2 = 0.56418958354775628694807945156077.. radius
^2 = 0.31830988618379067153776752674503.. radius^2
x Pi = 1 (the Area), and sqrt(1) = 1 (the SoCS)

One Pi is enough for me when I'm really hungry :!:

Rod :)

Re: Paradise Trinity Day

Posted: Sun Aug 26, 2018 11:11 pm
by Amigoo
:flower: Re: Three Squares of Pi design
(SoCS = Side of Circle's Square)

:geek: Cartesian contrast of 3 squared circles
where SoCS = 2.0, sqrt(Pi), Pi/2
Diameters = 2(2/sqrt(Pi)), 2.0, sqrt(Pi)

Rod ... :bike: ... (shoppin' for 3 squares a la mode) :roll:

Re: Paradise Trinity Day

Posted: Mon Aug 27, 2018 12:34 pm
by Amigoo
:flower: Re: Three Squares of Pi design
(SoIS = Side of Inscribed Square)

A smaller squared circle was added, using a SoIS of that golden circle
to illustrate how this geometry propagates with these quadrature
"building blocks" of objects & angles in CSC Neighborhoods. 8)

Rod :D

Re: Paradise Trinity Day

Posted: Tue Aug 28, 2018 6:22 am
by Amigoo
:flower: Re: Perfect Slice design

This "Pi Fork" right triangle must be the definitive circle-squaring object :!:
with it's two longer lines and two next shorter lines having 2/sqrt(Pi) ratio
... and the two shortest lines having sqrt(Pi) line length ratio. 8)

Also, a longer line and it's complementary next shorter line
have sqrt(Pi) line length ratio. HCIT :?: :!: ... not to mention
that this object is composed of 3 similar right triangles. :roll

:idea: Apparently, for the circle to be squared by the Greek rules,
first creating this right triangle may be Step One. :finger:

Tip: Hypotenuse is circle's diameter. ;)

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Tue Aug 28, 2018 7:57 pm
by Amigoo
:flower: Re: Perfect Slice design

Geometers' secret: :roll
The magenta lines in the Scalenitweet design have equal length
when the circle is squared. These 3 lines connect similar points
(angles) of two CSC-related, circle-squaring scalene triangles.

Rod ... :bike: ... (shoppin' for Tweet Tweet ring tone) :roll:

Re: Paradise Trinity Day

Posted: Wed Aug 29, 2018 12:48 am
by Amigoo
:flower: Re: PS Redux design

Propagation of Perfect Slice geometry ...
convincing that sqrt(2) rules the Neighborhood :!:

:geek: The hypotenuse and side of an isosceles right triangle
easily propagate geometric objects by a factor of sqrt(2). 8)

Rod :D

Re: Paradise Trinity Day

Posted: Wed Aug 29, 2018 7:06 pm
by Amigoo
:flower: Re: PS Redux design*
Sqrt(2) rules the Neighborhood :!:
:cheers: Obviously, the 2/sqrt(Pi) right triangle ratio defines ...
a "detailed, recursive, and infinitely self-similar mathematical set",
a newly discovered Quadractal (quadrature + fractal)? 8)

* updated in http://aitnaru.org/images/Khristos_Voskrese.pdf

Rod :stars:

Re: Paradise Trinity Day

Posted: Thu Aug 30, 2018 12:12 am
by Amigoo
:flower: Re: PS Redux design*
Sqrt(2) rules the Neighborhood
:geek: Geometers' secret:

The magic of the Quadractal is that the hypotenuse of this right triangle defines a circle's diameter
and the long side the length of a side of that circle's area square. Since sqrt(2) is inherent in circles,
infinite propagation of geometric circle-squaring objects (this right triangle, scalene triangle,
isosceles trapezoid) becomes the "impossible" reality.

The boundaries of Heaven and Earth adjoin ... apparently. :farao:

Rod :D

Re: Paradise Trinity Day

Posted: Thu Aug 30, 2018 11:22 pm
by Amigoo
:flower: Re: Scalenifiable design
"Sqrt(2) also rules this Neighborhood"

:geek: Geometers' secret:
Quadrature is confirmed by a squared circle's scalenifiability. :roll:

Rod :stars: (4-letter words are easier to pronounce)

Re: Paradise Trinity Day

Posted: Fri Aug 31, 2018 2:06 am
by Amigoo
:flower: Re: Scalenifiable design
"Sqrt(2) also rules this Neighborhood"

Adding more lines was easier than thinking of four 4-letter words
to substitute for the 16-letter tongue twister "scalenifiability".
Besides, these lines help confirm scalenifiabilty :!:

The red 'H' is best associated with HCIT! 8)

Rod :D

Re: Paradise Trinity Day

Posted: Fri Aug 31, 2018 11:22 am
by Amigoo
:flower: Re: Scalenifiable design
"Sqrt(2) also rules this Neighborhood"

:geek: Geometers' secret:
(sqrt(Pi) x sqrt(2)) / (sqrt(Pi) / sqrt(2)) = 2

(1.7724538509055160272981674833411..
x 1.4142135623730950488016887242097..)
/
(1.7724538509055160272981674833411..
/ 1.4142135623730950488016887242097..)
= 2

Rod :D

Re: Paradise Trinity Day

Posted: Sat Sep 01, 2018 11:33 am
by Amigoo
:flower: Re: Scalenifiable design
"Sqrt(2) also rules this Neighborhood"

Embellished to show that the hypotenuse of an isosceles right triangle
squares the largest circle and the side squares its sqrt(2) sibling. 8)

:cheers: "Lines and triangles and squares! Oh, Pi!"

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Sat Sep 01, 2018 7:37 pm
by Amigoo
:flower: Re: Trinitized Scalenity design
(exploration of Scalenifiable geometry)

Simply connecting available points revealed a higher-level,
circle-squaring scalene triangle and its squared circle. 8)

Quadrature to infinity :!:

Rod :D

Re: Paradise Trinity Day

Posted: Sun Sep 02, 2018 1:55 am
by Amigoo
:flower: Re: Trinitized Scalenity design
"Geometry that speaks for itself" 8)

Simplified for better contrast of the circle-squaring scalene triangles.

The large red scalene is in the same Cartesian position as when
I first recognized that this triangle had quadraturial significance
... and it resolved my evolving pre-condition that quadrature
must display the "marriage" of sqrt(Pi) and sqrt(2). ;)

Rod ... :bike: ...