Page 73 of 185

Re: Paradise Trinity Day

Posted: Tue Sep 01, 2015 6:06 am
by Amigoo
:flower: Re: Paleo Pi Pointers design (Pinary Vise)

Research notes ... :roll
Bookends pattern persistence table. :scratch:
(4/2 ratio maintained as Pi decrements)

[ 4.00000 ~ Pi/01 ~ 2.00000 ] 4(1)= 4/2 =1(2)
[ 2.00000 ~ Pi/02 ~ 1.00000 ] 2(2)= 4/2 =2(1)
[ 1.00000 ~ Pi/04 ~ 0.50000 ] 1(4)= 4/2 =4(.5)
[ 0.50000 ~ Pi/08 ~ 0.25000 ] .5(8)= 4/2 =8(.25)
[ 0.25000 ~ Pi/16 ~ 0.12500 ] .25(16)= 4/2 =16(.125)
[ 0.12500 ~ Pi/32 ~ 0.06250 ] .125(32)= 4/2 =32(.0625)
[ 0.06250 ~ Pi/64 ~ 0.03125 ] .0625(64)= 4/2 =64(.03125)

:? Hmmm ... how does Pi/trillions relate to 4/2?

Rod ... :bike: ... (off to find Bluebell) ;)

Re: Paradise Trinity Day

Posted: Wed Sep 02, 2015 10:30 am
by Amigoo
:flower: Re: Paleo Pi Pointers design (Pinary Vise)

Research notes ... :roll

Bookends 2.0 ~ Pi/2 ~ 1.0
2.0
x 1.1283791670955125738961589031215..
= 1.7724538509055160272981674833411.. sqrt(Pi) ;)
x 1.1283791670955125738961589031215..
= 1.5707963267948966192313216916398.. Pi/2
x 0.6366197723675813430755350534900..
1.0

Rod :D

Re: Paradise Trinity Day

Posted: Wed Sep 02, 2015 3:45 pm
by Amigoo
:flower: Re: Paleo Pi Pointers design (Pinary Vise)

Research notes ... :roll

Since bookends represent enclosure of a decrement of Pi
between two whole numbers, the math creates ...
"The Mystique of the Pi Corral", :?
starring 2(sqrt(1/Pi)):

:geek: Bookends 2.0 ~ Pi/2 ~ 1.0
2.0
x 1.1283791670955125738961589031215..
= 1.7724538509055160272981674833411.. sqrt(Pi)
x 1.1283791670955125738961589031215..
= 1.5707963267948966192313216916398.. Pi/2
x 0.6366197723675813430755350534900..
1.0

:idea: Therefore (restatement) ...

(1.1283791670955125738961589031215..)^2
= 1.2732395447351626861510701069801..

2 / 1.2732395447351626861510701069801..
= 1.5707963267948966192313216916399.. Pi/2

:stars: Therefore (the mystique) ...
2 / something squared = Pi/2,
a transcendental number? :shock:

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Thu Sep 03, 2015 7:44 am
by Amigoo
:flower: Re: Paleo Pi Pointers design (Pinary Vise)
Since bookends represent enclosure of a decrement of Pi between two whole numbers,
the math creates ... "The Mystique of the Pi Corral", starring 2(sqrt(1/Pi)):
:idea: Therefore (transcendental math) ...
The final decimal digit of Pi can be determined by
calculating backward from 4 and forward from 2
... until the 2/3 to 1/3 boundary is located. :shock:

:scratch: Say what? Three pieces of Pi.

Rod :hithere :hithere :hithere

Re: Paradise Trinity Day

Posted: Thu Sep 03, 2015 9:09 am
by Amigoo
:flower: Re: Paleo Pi Pointers design (Pinary Vise)
The final decimal digit of Pi can be determined by
calculating backward from 4 and forward from 2
... until the 2/3 to 1/3 boundary is located.
"Hmmm ... 2/3 and 1/3 of what?"

Rod :stars:

Re: Paradise Trinity Day

Posted: Fri Sep 04, 2015 5:33 pm
by Amigoo
:flower: Re: Paleo Pi Pointers design (Pinary Vise)
2/3 and 1/3 of what?"
A rhetorical question - answer is 2(sqrt(1/Pi)).
But what is the significance of these values?

:geek: Here's the 2/3 to 1/3 math perspective:

2(sqrt(1/Pi))
= 1.1283791670955125738961589031215..
^2 = 1.2732395447351626861510701069801..
/2 = 0.6366197723675813430755350534900..

1.2732395447351626861510701069801..
+ 0.6366197723675813430755350534900..

= 1.90985931710274402922660516047..
/ 1.2732395447351626861510701069801..
= 0.66666666666666666666666666666667..

= 1.90985931710274402922660516047..
/ 0.6366197723675813430755350534900..
= 0.33333333333333333333333333333333..

:idea: [ calculate up/down from Pi in this bookend ]

= 4.0
x 1.1283791670955125738961589031215..
= 3.5449077018110320545963349666806.. 2(sqrt(Pi))
x 1.1283791670955125738961589031215..
> 3.1415926535897932384626433832795.. Pi
x 0.6366197723675813430755350534900..
= 2.0

= 4.0
x 1.2732395447351626861510701069801..
> 3.1415926535897932384626433832795.. Pi
x 0.6366197723675813430755350534900..
= 2.0

Rod ... :bike: ... (off to find 1/3 of a pie)

Re: Paradise Trinity Day

Posted: Sat Sep 05, 2015 1:52 am
by Amigoo
:flower: Re: Paleo Pi Pointers design (Pinary Vise)

There it is! (1/Pi): :cheers:

1.90985931710274402922660516047..
/ 6 = 0.318309886183790671537767526745.. = 1/Pi 8)

1.90985931710274402922660516047..
/ 1.2732395447351626861510701069801.. = 1.5

1.90985931710274402922660516047..
/ 0.6366197723675813430755350534900.. = 3.0

Rod ... :bike: ... (off to find more 1/3 pie)

Re: Paradise Trinity Day

Posted: Sun Sep 06, 2015 2:55 am
by Amigoo
:flower: Re: Pinary Vise (new design)

"But that Pinary Vise! Where does it end? (or begin?)"
:colors: A simple design, colorfully bold and pointed:
http://aitnaru.org/images/Veritas_27597e.pdf

Rod :D

Re: Paradise Trinity Day

Posted: Mon Sep 07, 2015 3:22 am
by Amigoo
:flower: Re: Pinary Vise design
"But that Pinary Vise! Where does it end? (or begin?)"

A low calorie dessert (small bowl of numbers) after supper tonight:
(defines relationship of diagonals of upward pointing triangles)

:geek: 2(sqrt(1/Pi)) = sqrt(Pi) / (Pi/2)

1.1283791670955125738961589031215..
= 1.7724538509055160272981674833411..
/ 1.5707963267948966192313216916398..
= 1.1283791670955125738961589031215..

Rod :D

Re: Paradise Trinity Day

Posted: Mon Sep 07, 2015 5:28 pm
by Amigoo
:flower: Re: Pinary Vise design
"But that Pinary Vise! Where does it end? (or begin?)"

The rest of the story ...
(design also revised)

:geek: 2/(sqrt(Pi)) = sqrt(Pi)/(Pi/2) = 2(sqrt(1/Pi))

2 / 1.7724538509055160272981674833411..
= 1.7724538509055160272981674833411..
/ 1.5707963267948966192313216916398..
= 1.1283791670955125738961589031215..

Rod :D

Re: Paradise Trinity Day

Posted: Sat Sep 12, 2015 5:07 am
by Amigoo
:flower: Re: Pinary Vise design
"But that Pinary Vise! Where does it end? (or begin?)"

:cheers: The rest of the story ...
(design also revised ... again) :roll:
with mirror image of Yin and Yang symbolism. 8)

4(sqrt(1/Pi))/2 = 2/(sqrt(Pi)) = sqrt(Pi)/(Pi/2) = 2(sqrt(1/Pi))

2.256758334191025147792317806242..
/ 1.1283791670955125738961589031215..
= 2.0 ;)
/ 1.1283791670955125738961589031215..
= 1.7724538509055160272981674833411..
/ 1.1283791670955125738961589031215..
= 1.5707963267948966192313216916398..

Rod ... :bike: ... (off to find Yin/Yang balance)

:hithere See also: Floor Plan 001 design:
"Six of one – half a dozen of the other."

Re: Paradise Trinity Day

Posted: Sat Sep 12, 2015 4:07 pm
by Amigoo
:flower: Re: Pinary Vise design
"But that Pinary Vise! Where does it end? (or begin?)"

:roll Yin/Yang balance with hypergeometric essence:

4(sqrt(1/Pi))/2 = 2/(sqrt(Pi)) = sqrt(Pi)/(Pi/2)
= (Pi/2)/(Pi(sqrt(Pi)/4)) = 2(sqrt(1/Pi))

2.256758334191025147792317806242..
/ 1.1283791670955125738961589031215..
= 2.0
/ 1.1283791670955125738961589031215..
= 1.7724538509055160272981674833411..
/ 1.1283791670955125738961589031215..
= 1.5707963267948966192313216916398..
/ 1.1283791670955125738961589031215..
= 1.3920819992079269613212044955304..

Rod ... :bike: ... (off to comprehend "hypergeometric") :stars:

Re: Paradise Trinity Day

Posted: Sun Sep 13, 2015 4:11 am
by Amigoo
:flower: Re: Pinary Vise design
"But that Pinary Vise! Where does it end? (or begin?)"

:idea: Top and bottom sides of irregular quadrilaterals (red, magenta;
one right angle; "X" appears inside) have unique relationship:

Top = 0.92650275035220848584275966758914..
/ 0.52272320087706331513679711195272..
= 1.7724538509055160272981674833411.. sqrt(Pi)

Bottom = 0.52272320087706331513679711195272..
/ 0.92650275035220848584275966758914..
= 0.56418958354775628694807945156077.. sqrt(1/Pi)

0.56418958354775628694807945156077..
x 2 = 1.1283791670955125738961589031215.. 2(sqrt(1/Pi))

Rod :D

Re: Paradise Trinity Day

Posted: Sun Sep 13, 2015 3:09 pm
by Amigoo
:flower: Re: Pinary Vise design
"But that Pinary Vise! Where does it end? (or begin?)"
Yin/Yang balance with hypergeometric essence
:idea: "Hypergeometric" may refer to comparison of half to whole;
circle within circle having diameter equal to radius of larger circle.
In this comparison, a geometric "limit" may be found (calculated).

Rod :stars:

Re: Paradise Trinity Day

Posted: Sat Sep 19, 2015 5:15 am
by Amigoo
:flower: Re: CosPi 2.0 design
"The subtle cosine wave of squared circles." :hithere

Rod ... :bike: ... :sunny:

Re: Paradise Trinity Day

Posted: Tue Sep 22, 2015 3:33 pm
by Amigoo
:flower: Re: CosPi 2.0 design
"The subtle cosine wave of squared circles." :hithere

:duh A week later and the design is still being updated.
But with identification of the "smile of Pythagoras"
(rotate design clockwise 90 degrees), today's update
may be the final. At least, the Texas 'T' portion
seems to contain the salient right triangles. :finger:

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Sat Sep 26, 2015 4:39 am
by Amigoo
:flower: Re: Tripartite Soul (new design concept)
"Squared circle harmony of 2, sqrt(2), sqrt(Pi)"
The reason for spirit pleasure? ;)

Having been reduced to a simple design (where its soul was discovered),
this geometric concept now awaits harmony of colors. :colors:

Rod :D

Re: Paradise Trinity Day

Posted: Sat Sep 26, 2015 7:07 am
by Amigoo
:flower: Re: Tripartite Soul
"Squared circle harmony of 2, sqrt(2), sqrt(Pi)"

Who knew?
Squared circle geometry even speaks Plato! :roll:

;) But everyone knows: sqrt(2)/2 = .707..

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Sun Sep 27, 2015 2:30 am
by Amigoo
:flower: Re: Tripartite Soul
"Squared circle harmony of sqrt(2), 2, sqrt(Pi);
a correlation of three similar quadrilaterals."

Since the geometric essence is the quadrilateral
(three similar), the largest is now highlighted. :roll

Rod :D

Re: Paradise Trinity Day

Posted: Thu Oct 01, 2015 8:37 am
by Amigoo
:flower: Re: Tripartite Soul
"Squared circle harmony of sqrt(2), 2, sqrt(Pi);
a correlation of three similar quadrilaterals."

The circle-squaring scalene triangle insisted on obvious presence. :roll:
:roll Diameters from smallest to largest: 1, sqrt(2), sqrt(Pi), 2

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Thu Oct 01, 2015 4:17 pm
by Amigoo
:flower: Re: Tripartite Soul
"Squared circle harmony of 1,sqrt(2),sqrt(Pi),2
in a correlation of 3 similar quadrilaterals."

The inspiration to title this difficult, integrated geometry
preceded my understanding of how the title related. ;)

:cheers: I now see that 3 circles (green; D = 1, sqrt(2), 2)
are squared by the yellow circle (D = sqrt(Pi)) with its
inscribed square:

:geek: Radius squares green circle D = 1
Diameter squares green circle D = 2
Side of inscribed square squares green circle D = sqrt(2)

With this geometry, if there's any doubt that sqrt(Pi)
is the square of a circle whose diameter = 2,
geometers' minds are not participating. :roll:

8) A convincing Cartesian doodle for 10/10/15
(Paradise Trinity Day, 2015)

Rod :D

Re: Paradise Trinity Day

Posted: Sat Oct 03, 2015 1:23 am
by Amigoo
:flower: Re: Tripartite Soul
"Squared circle harmony of 1,sqrt(2),sqrt(Pi),2
in a correlation of 3 similar quadrilaterals."
A convincing Cartesian doodle
Having dared to think - even for a second - that this was not
serious geometry, I was given an assignment: Locate the next
circle in the decreasing progression 2, sqrt(Pi), sqrt(2), 1 :shock:

:idea: Even this Geometer Junior knew that the next diameter
will be sqrt(2)/2 ... but where is this circle? Obviously, near
the center of this Cartesian neighborhood and sharing a point
on the circumference of the next largest circle (D = 1).

Long story short: There it is! :hithere
As easy as 1,2,3 ;)

Rod ... :bike: ...

Re: Paradise Trinity Day

Posted: Sat Oct 03, 2015 4:52 am
by Amigoo
:flower: Re: Tripartite Soul
"Squared circle harmony of 1,sqrt(2),sqrt(Pi),2
in a correlation of 3 similar quadrilaterals."

See updated: http://aitnaru.org/images/Veritas_27597e.pdf

For extra credit, I could provide the
Geometry numbers of Tripartite Soul
(to calculate side of circles' square)

What? Eat more Pi? Twist my arm :!:

Rod :stars: (now full of Pi - need lotsa cake
... and ice cream) :roll:

Re: Paradise Trinity Day

Posted: Sat Oct 03, 2015 5:55 pm
by Amigoo
:flower: Re: Tripartite Soul (final summary :finger: )
"Squared circle harmony of 2,sqrt(2),1 and sqrt(Pi)
in a correlation of four similar quadrilaterals."

(aka, "a circle squared up, down, and sideways") :roll:

Geometry numbers of Tripartite Soul
(to calculate side of circle's square)

D = 2.0
/ 1.1283791670955125738961589031215.. 2(sqrt(1/Pi))
= 1.7724538509055160272981674833411.. sqrt(Pi)

D = 1.4142135623730950488016887242097.. sqrt(2)
/ 1.1283791670955125738961589031215.. 2(sqrt(1/Pi))
= 1.2533141373155002512078826424055.. sqrt(Pi/2)

D = 1.0
/ 1.1283791670955125738961589031215..
= 0.88622692545275801364908374167057.. sqrt(Pi)/2

D = 1.7724538509055160272981674833411.. sqrt(Pi)
/ 1.1283791670955125738961589031215..
= 1.5707963267948966192313216916405.. Pi/2

For reference (next circle in progression):

D = 0.70710678118654752440084436210485.. sqrt(2)/2
/ 1.1283791670955125738961589031215..
= 0.62665706865775012560394132120276..

:scratch: Hmmm ... interesting constant, this 2(sqrt(1/Pi))
(= 1.1283791670955125738961589031215.. )

Rod :D

Re: Paradise Trinity Day

Posted: Sat Oct 03, 2015 11:33 pm
by Amigoo
:flower: Re: Tripartite Soul (final summary :finger: )
"Squared circle harmony of 2,sqrt(2),1 and sqrt(Pi)
in a correlation of four similar quadrilaterals."
four similar quadrilaterals
:duh Now it's in, now it's out, now it's in ...

I was reluctant to add the fourth green circle because I would have to draw its inscribed quadrilateral. But I noticed an easy solution: the four circles (three green, one yellow) all had similar quadrilaterals and I had claimed "four". So, I could draw the fourth green circle (a similar geometric arc) but not its inscribed quadrilateral.

Say what? It's alluded to in the Numbers (D = sqrt(2)/2). :roll

Rod ... :bike: ... (not saving on the Quadrilateral Expressways (QE)) :roll: