
(aka "The Art of Pi")
Simplified (even the PDF):
http://aitnaru.org/images/Quinale!.pdf
Rod

If c = 2, a = sqrt(Pi), b = sqrt(4-Pi)
To square the circle one must circle the square
To square the circle one must circle the square
* updated in: http://aitnaru.org/images/Quinale!.pdfTo square the circle one must circle the square
Nested circles all squared, simplified with salience.To square the circle one must circle the square
To square the circle one must circle the square
To square the circle one must circle the square
To square the circle one must circle the square