
Re: Four Corner Pi design
"Pi are square!" Indeed!

Furthermore (actual Diameter of circle) ...
Given: Circle's Diameter = Pi/2 and SoCS = (Pi/2)/(2/sqrt(Pi))
hypotenuse, side of enclosing isosceles right triangle (IRT)
1.3920819992079269613212044955297.. (Pi/2)/(2/sqrt(Pi))
x 1.1283791670955125738961589031215.. 2/sqrt(Pi)
= Pi/2.. hypotenuse of IRT, Diameter of circle
1.3920819992079269613212044955297.. (Pi/2)/(2/sqrt(Pi))
/ 1.2533141373155002512078826424055.. (sqrt(Pi)sqrt(2))/2
= 1.1107207345395915617539702475152.. (Pi/2)/sqrt(2), side of IRT
1.2533141373155002512078826424055.. (sqrt(Pi)sqrt(2))/2
/ 1.1283791670955125738961589031215.. 2/sqrt(Pi)
= 1.1107207345395915617539702475152.. (Pi/2)/sqrt(2), side of IRT
Rod ...

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