
Focus on the divisibility of Pi by 2 and sqrt(2).


The "arrow" of the dark blue "bow & arrow" identifies the sqrt(2) line
sandwiched between hypotenuse and side of an isosceles right triangle,
lengths equal to sqrt(Pi) and (sqrt(Pi)(sqrt(2))/2, respectively.

Of course

= 1.4142135623730950488016887242097.. sqrt(2)
/ 1.2533141373155002512078826424055.. (sqrt(Pi)(sqrt(2))/2
= 1.1283791670955125738961589031215.. 2/sqrt(Pi),
authenticating ratio of hypotenuse to long side
of a circle-squaring right triangle.

Rod ...

re: "SMU Pi Burgers and Phries")