
Re: Simpli_city design
replicating quadrilateral identifies the CSC simplicity
OMG

Squared circle quadrilaterals contain a provable puissant property!
Straight lines connecting the midpoints of the Q' lines form a parallelogram.
Such power of the 'P' (words)!

, especially considering ...

A straight line connecting opposite points of the parallelogram
divide this geometric object in half ... precisely.

Since these Qs
are composed of two triangles, one right and one very right (isosceles)
... and since the one right contains a long line (not hypotenuse)
representing a side of the circle's square, transformation of
the Q to P then /2 effectively divides the Pi portion in half
... precisely

Now this is transcendental 'P'.
Rod
