Paradise Trinity Day

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
( http://aitnaru.org/images/Khristos_Voskrese.pdf )
Circlesquaring scalene and Pythagorean right triangles
are united by the ubiquitous sqrt(2). Who knew
"Either sqrt(2) is transcendental or Pi is not."
That is, the Pi associated with circles squared 
not necessarily the Pi of advanced math.
Nevertheless y'all, keep cheering faux Pi!
(as geometers say down in Texas)
Rod
( http://aitnaru.org/images/Khristos_Voskrese.pdf )
Circlesquaring scalene and Pythagorean right triangles
are united by the ubiquitous sqrt(2). Who knew
"Either sqrt(2) is transcendental or Pi is not."
That is, the Pi associated with circles squared 
not necessarily the Pi of advanced math.
Nevertheless y'all, keep cheering faux Pi!
(as geometers say down in Texas)
Rod

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
Sqrt(2) explains how the Pythagorean right and scalene triangles
both use 2/sqrt(Pi) to square the circle (side of circle's square):
Scalene's short side is side of inscribed square, multiplied by sqrt(2)
gives circle's diameter, thus geometry of Pythagorean right.
If a Pythagorean right is right, is a Pythagorean left right?
Rod ... ...
Geometers' secret:Circlesquaring scalene and Pythagorean right triangles
are united by the ubiquitous sqrt(2). Who knew
Sqrt(2) explains how the Pythagorean right and scalene triangles
both use 2/sqrt(Pi) to square the circle (side of circle's square):
Scalene's short side is side of inscribed square, multiplied by sqrt(2)
gives circle's diameter, thus geometry of Pythagorean right.
If a Pythagorean right is right, is a Pythagorean left right?
Rod ... ...

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
Some geometers already know about Quadrature!
... since it's "in the box" in this Neighborhood.
Rod
Some geometers already know about Quadrature!
... since it's "in the box" in this Neighborhood.
Rod

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
Who knew
The local universe has eyes on the box
... of this advancing inhabited planet.
Rod ... ...
Who knew
The local universe has eyes on the box
... of this advancing inhabited planet.
Rod ... ...

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
of approaching first contact with mortals of another planet.
"Mortals" is operative perspective since this contact
will not be with oncemortals (advancing spirit beings) 
we can do that already, as evidenced by 1111angels.
Rod
"Moon eyes" hint that this Quadrature is akin to symbolic heraldThe local universe has eyes on the box
of approaching first contact with mortals of another planet.
"Mortals" is operative perspective since this contact
will not be with oncemortals (advancing spirit beings) 
we can do that already, as evidenced by 1111angels.
Rod

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
Quadrature, as two circles squared ajointed by sqrt(2),
defines a parallelogram with 135 and 45 degrees.
(and inscribed "in the box")
Note: "ajointed" is allusion to "anoited".
Rod ... ...
Geometers' secret (Q.i.D.) ...The local universe has eyes on the box
Quadrature, as two circles squared ajointed by sqrt(2),
defines a parallelogram with 135 and 45 degrees.
(and inscribed "in the box")
Note: "ajointed" is allusion to "anoited".
Rod ... ...

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
Today's best guess: The circuits are open.
Rod
Who knows why so much symmetric busynessThe local universe has eyes on the box
Today's best guess: The circuits are open.
Rod

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
A circlesquaring Pythagorean right triangle, inscribed in a half circle,
unfolds geometrically to reveal the circlesquaring scalene.
"Today, I've half a mind to square the circle!"
Rod ... ...
Who knewThe local universe has eyes on the box
A circlesquaring Pythagorean right triangle, inscribed in a half circle,
unfolds geometrically to reveal the circlesquaring scalene.
"Today, I've half a mind to square the circle!"
Rod ... ...

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
Obviously, Pi is evenly divisible by sqrt(2), thus by 2.
Rod (counting transcendental stars, 2 by 2)
Now, that half a mind has half a mind to square again.Today, I've half a mind to square the circle!
Obviously, Pi is evenly divisible by sqrt(2), thus by 2.
Rod (counting transcendental stars, 2 by 2)

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
(updated in: http://aitnaru.org/images/Khristos_Voskrese.pdf )
Rod
(updated in: http://aitnaru.org/images/Khristos_Voskrese.pdf )
Now, that half a mind has half a mind has half a mind to square again.Today, I've half a mind to square the circle!
Rod

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Re: Paradise Trinity Day
Re: Quadrature in Duality design
Note the length relationship of the red diagonals that geometrically unite
the circlesquaring scalene and Pythagorean right triangles; HCIT
two similar triangles in two similar quadrilaterals.
Technically, three similar triangles in two similar quadrilaterals
since the similar isosceles rights are integrated into this trinity.
Rod ... ...
... with confirmation that two circles squared have sqrt(2) relationship:that half a mind has half a mind has half a mind to square again.
Note the length relationship of the red diagonals that geometrically unite
the circlesquaring scalene and Pythagorean right triangles; HCIT
two similar triangles in two similar quadrilaterals.
Technically, three similar triangles in two similar quadrilaterals
since the similar isosceles rights are integrated into this trinity.
Rod ... ...

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Re: Paradise Trinity Day
Re: Quadrature Unfolded design
Re: https://www.youtube.com/watch?v=n6PlzqALFzo
Our house is a very very fine house, with two Quads in the yard
(and two Quads in the house) ... life used to be so hard ...
now everything is easy cause of sqrt(2).
Rod
About the House of Pi where Pi are Square ..."that half a mind has half a mind has half a mind to square again."
with confirmation that two circles squared have sqrt(2) relationship:
Re: https://www.youtube.com/watch?v=n6PlzqALFzo
Our house is a very very fine house, with two Quads in the yard
(and two Quads in the house) ... life used to be so hard ...
now everything is easy cause of sqrt(2).
Rod

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Re: Paradise Trinity Day
Re: Quadrature Unfolded design
Who knew Pi is evenly divisible by 16:
Pi, as side of a circle's square and hypotenuse of an isosceles right triangle,
defines a 360degree spiral of adjoined isosceles rights.
But runnin' in squared circles is not scheduled.
Rod
Who knew Pi is evenly divisible by 16:
Pi, as side of a circle's square and hypotenuse of an isosceles right triangle,
defines a 360degree spiral of adjoined isosceles rights.
But runnin' in squared circles is not scheduled.
Rod

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Re: Paradise Trinity Day
Re: Quadrature 360 design
Runnin' in squared circles is scheduled (at least one lap).
Rod
Runnin' in squared circles is scheduled (at least one lap).
Rod

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Re: Paradise Trinity Day
Re: Quadrature 360 design
Proof that Pi is divisible by 16 (simplified geometry).
At least, in the House of Pi where Pi are Square
... in this local universe.
Rod ... ...
Proof that Pi is divisible by 16 (simplified geometry).
At least, in the House of Pi where Pi are Square
... in this local universe.
Rod ... ...

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Re: Paradise Trinity Day
Re: Quadrature 360 design
Must be true I typed the PDF page caption "Pi are square",
then OpenOffice software inserted "Pi are squaredcircle"
... unless there's an unseen typist lurking nearby.
Rod
Must be true I typed the PDF page caption "Pi are square",
then OpenOffice software inserted "Pi are squaredcircle"
... unless there's an unseen typist lurking nearby.
Rod

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Re: Paradise Trinity Day
Re: Quadrature 360 design
Now displaying the "impossible Rule of Quadrature (iRule)"
"Sez who?" Sqrt(2) and Noah: sqrt(2) x sqrt(2) ...
Rod
Now displaying the "impossible Rule of Quadrature (iRule)"
"Sez who?" Sqrt(2) and Noah: sqrt(2) x sqrt(2) ...
Rod

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Re: Paradise Trinity Day
Re: Quadrature 360 design
could define its own ruler (a design inspired by a discounted
sale item at a tourist kiosk on the ER Bridge)
Rod
Who knew ... that geometry of quadraturial persuasiondisplaying the "impossible Rule of Quadrature (iRule)
could define its own ruler (a design inspired by a discounted
sale item at a tourist kiosk on the ER Bridge)
Rod

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Re: Paradise Trinity Day
Re: Quadrature 360 design
... where 360 degree geometry constrains Pi
... and where sqrt(2) eats sqrt(Pi):
1.7724538509055160272981674833411.. sqrt(Pi)
x 1.4142135623730950488016887242097.. sqrt(2)
= 2.506628274631000502415765284811..
1.7724538509055160272981674833411.. sqrt(Pi)
/ 1.4142135623730950488016887242097.. sqrt(2
= 1.2533141373155002512078826424055..
2.506628274631000502415765284811..
/ 1.2533141373155002512078826424055..
= 2
Rod ... ... (Yum! 2X)
Tasty with a BaTampte spiral!
The Transcendental Pi Sandwichdisplaying the "impossible Rule of Quadrature (iRule)
... where 360 degree geometry constrains Pi
... and where sqrt(2) eats sqrt(Pi):
1.7724538509055160272981674833411.. sqrt(Pi)
x 1.4142135623730950488016887242097.. sqrt(2)
= 2.506628274631000502415765284811..
1.7724538509055160272981674833411.. sqrt(Pi)
/ 1.4142135623730950488016887242097.. sqrt(2
= 1.2533141373155002512078826424055..
2.506628274631000502415765284811..
/ 1.2533141373155002512078826424055..
= 2
Rod ... ... (Yum! 2X)
Tasty with a BaTampte spiral!

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Re: Paradise Trinity Day
Re: Quadrature 360 design (final, final)
in a twodimensional Cartesian Neighborhood of quadraturial ambience.
... with an ER Bridge lurking therein?
Rod
Obviously, Pi's transcendentalism begins anew every 360 degrees ...displaying the "impossible Rule of Quadrature" (iRule)
in a twodimensional Cartesian Neighborhood of quadraturial ambience.
... with an ER Bridge lurking therein?
Rod

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Re: Paradise Trinity Day
Re: Quadrature 360 design (final ^3)
... the host of the House of Pi where Pi are square?
Obviously, a wellordered, intelligent universe(s).
Rod ... ...
What?! There's a sqrt(2) spiral that encloses the Pi spiraldisplaying the "impossible Rule of Quadrature" (iRule)
... the host of the House of Pi where Pi are square?
Obviously, a wellordered, intelligent universe(s).
Rod ... ...

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Re: Paradise Trinity Day
Re: Quadrature 360 design
increases by sqrt(2), thus both spirals' growth factor is sqrt(2) for 360 degrees.
The line segments length ratio for both spirals maintains at 2/sqrt(Pi),
while segmenttosegment length within a spiral increases by sqrt(2).
Rod
Technically, Pi's transcendentalism begins anew every time circle's diameterPi's transcendentalism begins anew every 360 degrees
increases by sqrt(2), thus both spirals' growth factor is sqrt(2) for 360 degrees.
The line segments length ratio for both spirals maintains at 2/sqrt(Pi),
while segmenttosegment length within a spiral increases by sqrt(2).
Rod

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Re: Paradise Trinity Day
Re: Quadrature 360 design (more perspective)
increases by sqrt(2)  both spirals' growth factor is sqrt(2) for 360 degrees.
The line segments' length ratio for both spirals maintains at 2/sqrt(Pi),
while segmenttosegment length within a spiral increases by sqrt(2).
If this were a horse race, sqrt(2) is inner fence, increasing in length
with Pi on the inside of the track increasing its stride by sqrt(2) ...
imaginative analogy but you get the point(s).
With an infinite number of clubhouse turns, Pi seems to be
leading the fence, but following the track mandated by the fence,
and beggin' the question: Which came first Pi or sqrt(2)
Yet, we know from the geometry of quadrature that Pi = 2.
See also: https://www.youtube.com/watch?v=jUeIjZI32Jg
(quadrature insists there's no mathematical paradox)
Rod
Technically, Pi's transcendentalism begins anew every time circle's diameterPi's transcendentalism begins anew every 360 degrees
increases by sqrt(2)  both spirals' growth factor is sqrt(2) for 360 degrees.
The line segments' length ratio for both spirals maintains at 2/sqrt(Pi),
while segmenttosegment length within a spiral increases by sqrt(2).
If this were a horse race, sqrt(2) is inner fence, increasing in length
with Pi on the inside of the track increasing its stride by sqrt(2) ...
imaginative analogy but you get the point(s).
With an infinite number of clubhouse turns, Pi seems to be
leading the fence, but following the track mandated by the fence,
and beggin' the question: Which came first Pi or sqrt(2)
Yet, we know from the geometry of quadrature that Pi = 2.
See also: https://www.youtube.com/watch?v=jUeIjZI32Jg
(quadrature insists there's no mathematical paradox)
Rod

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Re: Paradise Trinity Day
Re: Quadrature 360 design (more perspective)
Re: https://www.youtube.com/watch?v=jUeIjZI32Jg
After scanning the comments (and understanding few of them ;  ), I suspect that this geometry may inspire serious discussion for ages ... which might even reveal that Pi is a mathematical invention not necessarily descriptive of circles all squared.
... if the discussion does not include sqrt(2), just move along Hopalong.
Rod
Re: https://www.youtube.com/watch?v=jUeIjZI32Jg
After scanning the comments (and understanding few of them ;  ), I suspect that this geometry may inspire serious discussion for ages ... which might even reveal that Pi is a mathematical invention not necessarily descriptive of circles all squared.
... if the discussion does not include sqrt(2), just move along Hopalong.
Rod

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Re: Paradise Trinity Day
Re: Quadrature 360 design (more perspective)
2/sqrt(Pi) is descriptive of a certain Pythagorean right triangle that squares the circle:
hypotenuse = circle's diameter and long side has length = side of circle's square (SoCS).
"iPi" (impossible Pi) is still first choice for this constant's name.
Rod ... ... (oft thinkin' "Mi Pi!" ...
more accurately "Pi! Pi!" (Pythagorean Pi).
P.S. (Pythagoras' Suggestion): "With Pythagorean Pi,
trigonometry becomes leaven to circles all squared."
Rod ... ... (off learnin' "What's trigonometry?")
However (re: 1.1283791670955125738961589031215..) ...Pi is a mathematical invention not necessarily descriptive of circles all squared.
2/sqrt(Pi) is descriptive of a certain Pythagorean right triangle that squares the circle:
hypotenuse = circle's diameter and long side has length = side of circle's square (SoCS).
"iPi" (impossible Pi) is still first choice for this constant's name.
Rod ... ... (oft thinkin' "Mi Pi!" ...
more accurately "Pi! Pi!" (Pythagorean Pi).
P.S. (Pythagoras' Suggestion): "With Pythagorean Pi,
trigonometry becomes leaven to circles all squared."
Rod ... ... (off learnin' "What's trigonometry?")