Paradise Trinity Day
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Re: Paradise Trinity Day
Re: https://apnews.com/fdb1408a077b4988a71be339e4c94c2e
"Karen Holt of Edwards, Mississippi, was with several people asking lawmakers to adopt a new banner with a magnolia, which is both the state tree and the state flower, and with stars to represent Mississippi as the 20th state. She said it would represent 'joy of being a citizen of the United States,' unlike the current flag."
All reflections of the glories of past wars can be retired ... eventually.
But like most emotive symbols/symbolism, it's less controversial to
introduce the new vision before rapid destruction of the old,
still cherished by many citizens.
But retaliation toppling of statues can be therapeutic.
Rod
"Karen Holt of Edwards, Mississippi, was with several people asking lawmakers to adopt a new banner with a magnolia, which is both the state tree and the state flower, and with stars to represent Mississippi as the 20th state. She said it would represent 'joy of being a citizen of the United States,' unlike the current flag."
All reflections of the glories of past wars can be retired ... eventually.
But like most emotive symbols/symbolism, it's less controversial to
introduce the new vision before rapid destruction of the old,
still cherished by many citizens.
But retaliation toppling of statues can be therapeutic.
Rod
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Re: Paradise Trinity Day
Re: https://www.dailymail.co.uk/news/articl ... ID-19.html
"I have zero symptoms (so far) and I feel fine. In fact, I ran 5 miles this morning."
"he was inside the rally for about 6 hours on Saturday at the BOK Center and that he wore a mask
and mostly practiced social distancing, except for when he went to the concourse to get a snack"
That he has no symptoms ("asymptomatic") is great! ...
except he can now infect others who might develop symptoms.
The world's focus on "masks" rarely discusses the effectiveness
of the MANY different (some homestyle) masks now being worn.
NO TESTING of these hints that they're just symbols of protection.
Then there's the problem of masks being reworn without cleaning.
Rod
"I have zero symptoms (so far) and I feel fine. In fact, I ran 5 miles this morning."
"he was inside the rally for about 6 hours on Saturday at the BOK Center and that he wore a mask
and mostly practiced social distancing, except for when he went to the concourse to get a snack"
That he has no symptoms ("asymptomatic") is great! ...
except he can now infect others who might develop symptoms.
The world's focus on "masks" rarely discusses the effectiveness
of the MANY different (some homestyle) masks now being worn.
NO TESTING of these hints that they're just symbols of protection.
Then there's the problem of masks being reworn without cleaning.
Rod
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Re: Paradise Trinity Day
Regarding previous posts ...
Must be the mask that prevented visual identification of the correct topic!
Mask or outdated bifocals or senior moment or low blood sugar (BS)
Rod
Must be the mask that prevented visual identification of the correct topic!
Mask or outdated bifocals or senior moment or low blood sugar (BS)
Rod
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Re: Paradise Trinity Day
Re: Our Two D2C2 design
Geometer's secret ...
Geometric contrast of two circles squared,
large where Diameter = 2, small where Circumference = 2
Who knew
Line length difference of circle-squaring right triangles
= 3.1415926535897932384626433832795...........
Rod
Geometer's secret ...
Geometric contrast of two circles squared,
large where Diameter = 2, small where Circumference = 2
Who knew
Line length difference of circle-squaring right triangles
= 3.1415926535897932384626433832795...........
Rod
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Re: Paradise Trinity Day
Re: Our Two D2C2 design*
"Finite dimension of the Neighborhood"
Geometer's secret ...
Another circle squared was inserted between the Two, with SoCS = 1,
D = 2/sqrt(Pi) = 1.1283791670955125738961589031215..
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod ... ...
"Finite dimension of the Neighborhood"
Geometer's secret ...
Another circle squared was inserted between the Two, with SoCS = 1,
D = 2/sqrt(Pi) = 1.1283791670955125738961589031215..
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod ... ...
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Re: Paradise Trinity Day
Re: Our Two D2C2 design
"Finite dimension of the Neighborhood"
Geometer's master secret ...
The large golden circle and enclosed golden square represent
a circle squared and a square circled ín a sqrt(2) continuum.
The difference in squares? Pi ... Who knew?!
Rod
"Finite dimension of the Neighborhood"
Geometer's master secret ...
The large golden circle and enclosed golden square represent
a circle squared and a square circled ín a sqrt(2) continuum.
The difference in squares? Pi ... Who knew?!
Rod
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Re: Paradise Trinity Day
Re: Our Two D2C2 design
"Finite dimension of the Neighborhood"
Geometer's secret extraordinaire ...
The circle-squaring right triangle of the large circle
defines circle-squaring right triangle of small circle,
therefore both circle and its square!
Tip: Small golden circle is not "small circle",
a good example of "esoteric".
Rod ... ...
"Finite dimension of the Neighborhood"
Geometer's secret extraordinaire ...
The circle-squaring right triangle of the large circle
defines circle-squaring right triangle of small circle,
therefore both circle and its square!
Tip: Small golden circle is not "small circle",
a good example of "esoteric".
Rod ... ...
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Re: Paradise Trinity Day
Re: Our Two D2C2 design
"Finite dimension of the Neighborhood"
Center circle contains a clue how to do this;
large circle-squaring triangle is not shown.
Center circle now suggests "Eye of Pi"
Tip: Small golden circle is not "small circle"
of the sqrt(2) continuum.
Rod
"Finite dimension of the Neighborhood"
Geometer's secret ...The circle-squaring right triangle of the large circle
defines circle-squaring right triangle of small circle
Center circle contains a clue how to do this;
large circle-squaring triangle is not shown.
Center circle now suggests "Eye of Pi"
Tip: Small golden circle is not "small circle"
of the sqrt(2) continuum.
Rod
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Re: Paradise Trinity Day
Re: Our Two D2C2 design
"Finite dimension of the Neighborhood"
Decreasing Transition Values (for sqrt(2) continuum)
A = Area, D = Diameter, SoCS = Side of Circle's Square
Circle to square: D = 2, sqrt(2), SoCS = 1, A(C) = Pi
Square to circle: SoCS = sqrt(Pi), Pi/2, D = 2/sqrt(Pi), A(c) = 1
Circle (D=2) to circle (Circumference=2)
D(C) = 2, SoCS = sqrt(Pi), A(C) = Pi
D(c) = ((2/sqrt(Pi))^2)/2, SoCS = (2/sqrt(Pi))/2, A(c) = 1/Pi
1/Pi = 0.31830988618379067153776752674503..
Pi/2 = 1.5707963267948966192313216916398..
sqrt(Pi) = 1.7724538509055160272981674833411..
2/sqrt(Pi) = 1.1283791670955125738961589031215..
Rod
"Finite dimension of the Neighborhood"
Decreasing Transition Values (for sqrt(2) continuum)
A = Area, D = Diameter, SoCS = Side of Circle's Square
Circle to square: D = 2, sqrt(2), SoCS = 1, A(C) = Pi
Square to circle: SoCS = sqrt(Pi), Pi/2, D = 2/sqrt(Pi), A(c) = 1
Circle (D=2) to circle (Circumference=2)
D(C) = 2, SoCS = sqrt(Pi), A(C) = Pi
D(c) = ((2/sqrt(Pi))^2)/2, SoCS = (2/sqrt(Pi))/2, A(c) = 1/Pi
1/Pi = 0.31830988618379067153776752674503..
Pi/2 = 1.5707963267948966192313216916398..
sqrt(Pi) = 1.7724538509055160272981674833411..
2/sqrt(Pi) = 1.1283791670955125738961589031215..
Rod
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Re: Paradise Trinity Day
Re: MC Square design
(Morbus Cyclometricus Square, "impossible" geometry tool)
aka "Entertainment = MC Squared", SoCS = Side of Circle's Square
"Calculates" squared circle's diameter or area (SoCS) of circle.
Long side, hypotenuse of right triangle have identical increments.
Arc drawn across both sides performs the calculation.
As accurate as a slide rule, depending on precision of construction,
but more popular as a spoof of "impossible" Quadrature.
Dimensions of circle-squaring right triangle (for angular reference):
hypotenuse (diameter) = 2, long side = sqrt(Pi), short side = sqrt(4-Pi)
Rod
(Morbus Cyclometricus Square, "impossible" geometry tool)
aka "Entertainment = MC Squared", SoCS = Side of Circle's Square
"Calculates" squared circle's diameter or area (SoCS) of circle.
Long side, hypotenuse of right triangle have identical increments.
Arc drawn across both sides performs the calculation.
As accurate as a slide rule, depending on precision of construction,
but more popular as a spoof of "impossible" Quadrature.
Dimensions of circle-squaring right triangle (for angular reference):
hypotenuse (diameter) = 2, long side = sqrt(Pi), short side = sqrt(4-Pi)
Rod
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Re: Paradise Trinity Day
Re: MC Square design*
(Morbus Cyclometricus Square, "impossible" geometry tool)
aka "Entertainment = MC Squared", SoCS = Side of Circle's Square
Better colors for the planet's new E=MC^2
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod ... ...
(Morbus Cyclometricus Square, "impossible" geometry tool)
aka "Entertainment = MC Squared", SoCS = Side of Circle's Square
Better colors for the planet's new E=MC^2
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod ... ...
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Re: Paradise Trinity Day
Re: MC Square design
(Morbus Cyclometricus Square, "impossible" geometry tool)
Now tuned to the Finite Key of Pi:
2/sqrt(Pi) = sqrt(Pi)/(Pi/2) = 2(sqrt(1/Pi)) = Q
Rod
(Morbus Cyclometricus Square, "impossible" geometry tool)
Now tuned to the Finite Key of Pi:
2/sqrt(Pi) = sqrt(Pi)/(Pi/2) = 2(sqrt(1/Pi)) = Q
Rod
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Re: Paradise Trinity Day
Re: MC Square design
"They who bite the moon bite the Sun"
"Say what?!"
Dunno! Might relate to karma.
Rod ... ...
New symbolism added with ethereal perspective.Now tuned to the Finite Key of Pi
"They who bite the moon bite the Sun"
"Say what?!"
Dunno! Might relate to karma.
Rod ... ...
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Re: Paradise Trinity Day
Re: MC Square design
... depending on what you sow.
Rod
It's possible to reap more than you sow,They who bite the moon bite the Sun
... depending on what you sow.
Rod
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Re: Paradise Trinity Day
Re: Nibbles & Bites design
"They who bite the moon bite the Sun"
Geometer's secret ...
Quadrature is like rabbits,
when tuned to the Finite Key of Pi:
2/sqrt(Pi) = sqrt(Pi)/(Pi/2) = 2(sqrt(1/Pi)) = Q
Rod ... ...
"They who bite the moon bite the Sun"
Geometer's secret ...
Quadrature is like rabbits,
when tuned to the Finite Key of Pi:
2/sqrt(Pi) = sqrt(Pi)/(Pi/2) = 2(sqrt(1/Pi)) = Q
Rod ... ...
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Re: Paradise Trinity Day
Re: Nibbles & Bites design*
"They who bite the moon bite the Sun"
(it's possible to reap more than you sow)
Quadrature's Long Story Short: Pi /2 … precisely!
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod
"They who bite the moon bite the Sun"
(it's possible to reap more than you sow)
Quadrature's Long Story Short: Pi /2 … precisely!
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod
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Re: Paradise Trinity Day
Re: Nibbles & Bites design
"They who bite the moon bite the Sun"
Geometer's secret ...
Of three circles squared ("like rabbits"),
Side of Circle's Square (SoCS) = 4, 2, 1
x 2/sqrt(Pi) = circle's diameter
Rod
"They who bite the moon bite the Sun"
Geometer's secret ...
Of three circles squared ("like rabbits"),
Side of Circle's Square (SoCS) = 4, 2, 1
x 2/sqrt(Pi) = circle's diameter
Rod
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Re: Paradise Trinity Day
Re: Diagonals, Juxtapositional design
Geometer's secret ...
Geometric proof that two srt(2)-related circles
have area squares also related by sqrt(2) ...
as evidenced by their trapezoidal diagonals.
"Say what?!"
Why?! It's perfectly Pythagorean!
Rod ... ...
Geometer's secret ...
Geometric proof that two srt(2)-related circles
have area squares also related by sqrt(2) ...
as evidenced by their trapezoidal diagonals.
"Say what?!"
Why?! It's perfectly Pythagorean!
Rod ... ...
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Re: Paradise Trinity Day
Re: Diagonals, Juxtapositional design
Geometer's secret ...
Three Significances complement the Quadraturial balance.
"What are the 'Three Significances'?" Go figure!
Or ask geometers of Quadraturial persuasion.
Rod
Geometer's secret ...
Three Significances complement the Quadraturial balance.
"What are the 'Three Significances'?" Go figure!
Or ask geometers of Quadraturial persuasion.
Rod
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Re: Paradise Trinity Day
Re: Diagonals, Juxtapositional design
Geometer's secret ...
Only geometers of Quadraturial persuasion have seen (and comprehend)
the new geometry tool, iQ Pro ("impossible" Quadrature Protractor).
Rod ... ...
Geometer's secret ...
Only geometers of Quadraturial persuasion have seen (and comprehend)
the new geometry tool, iQ Pro ("impossible" Quadrature Protractor).
Rod ... ...
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Re: Paradise Trinity Day
Re: Diagonals, Juxtapositional design
Even more simplification!
and convincing that "Sqrt(2) rules the Neighborhood!"
as evidenced by visual evaluation of iQ Pro
Rod
Even more simplification!
and convincing that "Sqrt(2) rules the Neighborhood!"
as evidenced by visual evaluation of iQ Pro
Rod
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Re: Paradise Trinity Day
Re: Diagonals, Juxtapositional design*
Geometer's secret ...
The Design Department decided to add one more line, but ...
Marketing caught it, immediately threatening to defund Design,
whereupon Design countered that it was not funded anyway.
"Final, final ... or else!" warned Marketing ... again.
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod ... ...
Geometer's secret ...
The Design Department decided to add one more line, but ...
Marketing caught it, immediately threatening to defund Design,
whereupon Design countered that it was not funded anyway.
"Final, final ... or else!" warned Marketing ... again.
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod ... ...
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Re: Paradise Trinity Day
Re: Diagonals, Juxtapositional design
There's that pesky '7' again
You would think that it's ...
"fundamental to universe organization"
... or "a word from our sponsor".
Rod
There's that pesky '7' again
You would think that it's ...
"fundamental to universe organization"
... or "a word from our sponsor".
Rod
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Re: Paradise Trinity Day
Re: Diagonals, Juxtapositional design
Geometer's secret ...
Hypotenuse of the inside of the '7' (a right triangle) is created by two lines
drawn perpendicular to two sides of the circle-squaring scalene triangle.
"Say what?!" That's sum Quadrature
Rod ... ...
Geometer's secret ...
Hypotenuse of the inside of the '7' (a right triangle) is created by two lines
drawn perpendicular to two sides of the circle-squaring scalene triangle.
"Say what?!" That's sum Quadrature
Rod ... ...
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Re: Paradise Trinity Day
Re: Diagonals, Juxtapositional design
Geometer's secret ...
The circle-squaring scalene triangle confirms conjecture ten years ago:
a geometric object uniting sqrt(Pi) and sqrt(2) would be the ultimate
Cartesian signature of a circle squared.
"Say what?!" That's sum Quadrature
Rod
Geometer's secret ...
The circle-squaring scalene triangle confirms conjecture ten years ago:
a geometric object uniting sqrt(Pi) and sqrt(2) would be the ultimate
Cartesian signature of a circle squared.
"Say what?!" That's sum Quadrature
Rod