Paradise Trinity Day

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Re: Paradise Trinity Day
Re: "TLO" design (aka "Three Moonsa Pi"),
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Who can tell
'7' may allude to "scalene" of the circlesquaring triangles ...
according to geometers at the Temple of Meganta at TLO.
Rod
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Who can tell
'7' may allude to "scalene" of the circlesquaring triangles ...
according to geometers at the Temple of Meganta at TLO.
Rod

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Re: Paradise Trinity Day
Re: "TLO" design (aka "Three Moonsa Pi")
A Pi divided against itself cannot stand ...
alone in a transcendental nirvana:
3.5449077018110320545963349666823.. 2(sqrt(Pi))
/ 3.1415926535897932384626433832795.. Pi
= 1.1283791670955125738961589031215.. 2/sqrt(Pi)
(defines a circlesquaring right triangle)
The next Real Wheel of Pi design is not
The Last One since this foundational geometry
was created last year then rolled forward.
This "Real Wheel of Pi, properly aged" design,
highlights Pi Corral with succinct concentricity:
For D = 2, SoIS = sqrt(2), SoCS = sqrt(Pi)
1.2533141373155002512078826424055.. (sqrt(2)sqrt(Pi))/2
x 1.1283791670955125738961589031215.. 2/sqrt(Pi)
= 1.4142135623730950488016887242096.. sqrt(2)
(BTW little D = 2/Pi, C = 2)
How did G101Qqq get in the toy box
("Geometry 101 with triple+ Quadrature")
Rod ... ...
A Pi divided against itself cannot stand ...
alone in a transcendental nirvana:
3.5449077018110320545963349666823.. 2(sqrt(Pi))
/ 3.1415926535897932384626433832795.. Pi
= 1.1283791670955125738961589031215.. 2/sqrt(Pi)
(defines a circlesquaring right triangle)
The next Real Wheel of Pi design is not
The Last One since this foundational geometry
was created last year then rolled forward.
This "Real Wheel of Pi, properly aged" design,
highlights Pi Corral with succinct concentricity:
For D = 2, SoIS = sqrt(2), SoCS = sqrt(Pi)
1.2533141373155002512078826424055.. (sqrt(2)sqrt(Pi))/2
x 1.1283791670955125738961589031215.. 2/sqrt(Pi)
= 1.4142135623730950488016887242096.. sqrt(2)
(BTW little D = 2/Pi, C = 2)
How did G101Qqq get in the toy box
("Geometry 101 with triple+ Quadrature")
Rod ... ...

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Re: Paradise Trinity Day
Re: "G101Qqq" design,
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
With Quadrature there is always better pattern
... when sqrt(2) manages the "impossible" Pi Corral.
The Cartesian clue that originated more than a decade ago
is that Quadrature depends on 8 points of a circle whereupon rests
the circle's square. Quadrature's geometry derives from this clue
... since the infinite points of a circle are insignificant!
For math nerds ...
This geometry suggests a decreasing value of Pi (not linear infinity)
as the nested sqrt(2) circles decrease in size. What progression
is this: if D = 2(sqrt(Pi)), SoCS = Pi , if D = 2, SoCS = sqrt(Pi),
if D = 1, SoCS = sqrt(Pi)/2
Regarding the '7' pattern ...
This natural pattern in sqrt(2)nested circles was believed
to associate with a soft chime at the Temple of Meganta,
a sound heard at every time display having a '7' digit;
146 times in a 24hour day. Perhaps but a myth.
Regarding '146' ... 1 x 4 x 6 = 2 x 4 = 8
= points on circle upon which rests circle's square.
Rod
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
With Quadrature there is always better pattern
... when sqrt(2) manages the "impossible" Pi Corral.
The Cartesian clue that originated more than a decade ago
is that Quadrature depends on 8 points of a circle whereupon rests
the circle's square. Quadrature's geometry derives from this clue
... since the infinite points of a circle are insignificant!
For math nerds ...
This geometry suggests a decreasing value of Pi (not linear infinity)
as the nested sqrt(2) circles decrease in size. What progression
is this: if D = 2(sqrt(Pi)), SoCS = Pi , if D = 2, SoCS = sqrt(Pi),
if D = 1, SoCS = sqrt(Pi)/2
Regarding the '7' pattern ...
This natural pattern in sqrt(2)nested circles was believed
to associate with a soft chime at the Temple of Meganta,
a sound heard at every time display having a '7' digit;
146 times in a 24hour day. Perhaps but a myth.
Regarding '146' ... 1 x 4 x 6 = 2 x 4 = 8
= points on circle upon which rests circle's square.
Rod

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Re: Paradise Trinity Day
Re: "Just Puzzling" design
It's just puzzling how Quadrature relates to Pythagorean squares
... especially considering that this design began as exploration
of the sqrt(2) spiral, apparent foundation of the Pi Corral.
Regarding large dark blue circle ...
D = 4, SoCS = 2(sqrt(Pi))
Obviously, Pi are equally square! ...
on both sides of this circle's diameter.
(transcendental / 2) / 2 .. comes to mind.
Rod
It's just puzzling how Quadrature relates to Pythagorean squares
... especially considering that this design began as exploration
of the sqrt(2) spiral, apparent foundation of the Pi Corral.
Regarding large dark blue circle ...
D = 4, SoCS = 2(sqrt(Pi))
Obviously, Pi are equally square! ...
on both sides of this circle's diameter.
(transcendental / 2) / 2 .. comes to mind.
Rod

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Re: Paradise Trinity Day
Re: "Just Puzzling" design,
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Quadrature's infinite nibbles of Pi by geometric Piranhas.
Essential formulary of the Pi Corral:
2 / 1.7724538509055160272981674833411.. ( 2/sqrt(Pi) )
= 1.1283791670955125738961589031215.. (defines unique right triangle)
^2 = 1.2732395447351626861510701069801..
Lotsa numbas for circlesquaring right triangle
inscribed in a circle whose Circumference = 4.0
a = 1.1283791670955125738961589031215.. 2/sqrt(Pi)
^2 = 1.27323954473516268615107010698..
b = 0.63661977236758134307553505349006.. ((2/sqrt(Pi))^2)/2
x 0.92650275035220848584275966758914.. (sqrt(4Pi))^2
= 0.58982997002716101129132484048001..
^2 = 0.34789939354224165695100130437553..
c = 1.27323954473516268615107010698.. (2/sqrt(Pi))^2
^2 = 1.6211389382774043431020714113555..
1.27323954473516268615107010698.. a^2
+ 0.34789939354224165695100130437553.. b^2
= 1.6211389382774043431020714113555.. c^2
Pop Quiz (from the School of Piranhas)
Q: When is area of a circle equal to its diameter?
A: When circle's circumference = 4 = Pi(D)
When Circumference = 4.0
Diameter = (2/sqrt(Pi))^2
SoCS = 2/sqrt(Pi)
Area = (2/sqrt(Pi))^2
= Diameter
Rod ... ...
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Quadrature's infinite nibbles of Pi by geometric Piranhas.
Essential formulary of the Pi Corral:
2 / 1.7724538509055160272981674833411.. ( 2/sqrt(Pi) )
= 1.1283791670955125738961589031215.. (defines unique right triangle)
^2 = 1.2732395447351626861510701069801..
Lotsa numbas for circlesquaring right triangle
inscribed in a circle whose Circumference = 4.0
a = 1.1283791670955125738961589031215.. 2/sqrt(Pi)
^2 = 1.27323954473516268615107010698..
b = 0.63661977236758134307553505349006.. ((2/sqrt(Pi))^2)/2
x 0.92650275035220848584275966758914.. (sqrt(4Pi))^2
= 0.58982997002716101129132484048001..
^2 = 0.34789939354224165695100130437553..
c = 1.27323954473516268615107010698.. (2/sqrt(Pi))^2
^2 = 1.6211389382774043431020714113555..
1.27323954473516268615107010698.. a^2
+ 0.34789939354224165695100130437553.. b^2
= 1.6211389382774043431020714113555.. c^2
Pop Quiz (from the School of Piranhas)
Q: When is area of a circle equal to its diameter?
A: When circle's circumference = 4 = Pi(D)
When Circumference = 4.0
Diameter = (2/sqrt(Pi))^2
SoCS = 2/sqrt(Pi)
Area = (2/sqrt(Pi))^2
= Diameter
Rod ... ...

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Re: Paradise Trinity Day
Re: "C=4~P=4" design,
added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf
"I thought that Harey Pi would be the end of me."
Geometer's secret (a riddle) ...
"A whimsical blending of concepts for this quiescing
Quadraturial juxtaposition of Circumference and Perimeter."
Addition of the "Pi Fork" reveals a better Harey Pi
... which reveals Circumference (circle of a square)
and Perimeter (square of a circle) having length = 4.
In time for Pi Day, March 14, the authentic Harey Pi
In the Pi Fork's circlesquaring right triangle,
each two colored lines have sqrt(Pi) relationship.
Rod ... ...
added to: http://aitnaru.org/images/Yin_Yang_Pi.pdf
"I thought that Harey Pi would be the end of me."
Geometer's secret (a riddle) ...
"A whimsical blending of concepts for this quiescing
Quadraturial juxtaposition of Circumference and Perimeter."
Addition of the "Pi Fork" reveals a better Harey Pi
... which reveals Circumference (circle of a square)
and Perimeter (square of a circle) having length = 4.
In time for Pi Day, March 14, the authentic Harey Pi
In the Pi Fork's circlesquaring right triangle,
each two colored lines have sqrt(Pi) relationship.
Rod ... ...

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Re: Paradise Trinity Day
Re: "C=4~P=4" design,
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Harey's new millennium mantra ...
"The circle cannot be squared, but squared circles exist!"
New theme for Pi Day 2021 ...
The universe asks "Can you hear me now? Put your ears on!"
Voted best song for a New Millennium Pi ...
https://www.youtube.com/watch?v=ZgsUXUBpS8Qthem
Voted best Pi for a New Millennium song ...
2/sqrt(Pi) = 1.1283791670955125738961589031215..
(defines an inscribed Pythagorean right triangle*
that defines a circle and its square)
* a = sqrt(4Pi), b = sqrt(Pi), c = 2 [or sqrt(4) = 2]
And then Pythagoras suggested
"Get Real! and ethereal! ... like me!"
Rod ... ...
updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Harey's new millennium mantra ...
"The circle cannot be squared, but squared circles exist!"
New theme for Pi Day 2021 ...
The universe asks "Can you hear me now? Put your ears on!"
Voted best song for a New Millennium Pi ...
https://www.youtube.com/watch?v=ZgsUXUBpS8Qthem
Voted best Pi for a New Millennium song ...
2/sqrt(Pi) = 1.1283791670955125738961589031215..
(defines an inscribed Pythagorean right triangle*
that defines a circle and its square)
* a = sqrt(4Pi), b = sqrt(Pi), c = 2 [or sqrt(4) = 2]
And then Pythagoras suggested
"Get Real! and ethereal! ... like me!"
Rod ... ...

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Re: Paradise Trinity Day
Re: "C=4~P=4" design*
"Quadraturial Salience of Scalenity",
aka "The Three Ts of Q" [pronounced "three tease"]
(circlesquaring Trapezoid, right Triangle, scalene Triangle)
"Impossible" Quadrature is best savored with a real Pi Fork
where 2line sets have sqrt(Pi) or 2/sqrt(Pi) relationship.
"So, is the circle finally squared?!"
Is it possible for the circle not to be squared?!
(yes, mathematically ... so they say)
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod ... ...
"Quadraturial Salience of Scalenity",
aka "The Three Ts of Q" [pronounced "three tease"]
(circlesquaring Trapezoid, right Triangle, scalene Triangle)
"Impossible" Quadrature is best savored with a real Pi Fork
where 2line sets have sqrt(Pi) or 2/sqrt(Pi) relationship.
"So, is the circle finally squared?!"
Is it possible for the circle not to be squared?!
(yes, mathematically ... so they say)
* updated in: http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod ... ...

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Re: Paradise Trinity Day
Re: "C=4~P=4" design
"Salience of Scalenity"
If you comprehend this esoteric geometry,
consider yourself "impossibly" mooned by symbolism
... worthy of the next Roswell craft.
Or this might be "esoterically integrated geometry
of Quadraturial perspective" (aka "Morbus iQ").
Speaking of Morbus iQ ...
Given circlesquaring right triangle
where a = sqrt(Pi), b = sqrt(4Pi), c = 2
"impossible" ratio of Quadrature (irQ)
a/b = ((a+b)/b)1
1.7724538509055160272981674833411.. sqrt(Pi)
/ 0.92650275035220848584275966758914.. sqrt(4Pi)
= 1.9130583802711007947403078280204..
2.6989566012577245131409271509303.. sqrt(Pi) + sqrt(4Pi)
/ 0.92650275035220848584275966758914.. sqrt(4Pi)
= 2.9130583802711007947403078280204..
1 = 1.9130583802711007947403078280204..
"Ps & Qs" of Pythagorean Quadrature:
Since a^2 + b^2 = c^2, Pi + (4Pi) = 4
Rod
"Salience of Scalenity"
If you comprehend this esoteric geometry,
consider yourself "impossibly" mooned by symbolism
... worthy of the next Roswell craft.
Or this might be "esoterically integrated geometry
of Quadraturial perspective" (aka "Morbus iQ").
Speaking of Morbus iQ ...
Given circlesquaring right triangle
where a = sqrt(Pi), b = sqrt(4Pi), c = 2
"impossible" ratio of Quadrature (irQ)
a/b = ((a+b)/b)1
1.7724538509055160272981674833411.. sqrt(Pi)
/ 0.92650275035220848584275966758914.. sqrt(4Pi)
= 1.9130583802711007947403078280204..
2.6989566012577245131409271509303.. sqrt(Pi) + sqrt(4Pi)
/ 0.92650275035220848584275966758914.. sqrt(4Pi)
= 2.9130583802711007947403078280204..
1 = 1.9130583802711007947403078280204..
"Ps & Qs" of Pythagorean Quadrature:
Since a^2 + b^2 = c^2, Pi + (4Pi) = 4
Rod

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Re: Paradise Trinity Day
Re: "C=4~P=4" design
"Salience of Scalenity"
Better color logic (both green squares square their respective circle).
Geometry that may have potential for a labyrinth (and might attract UFOs).
Rod ... ...
"Salience of Scalenity"
Better color logic (both green squares square their respective circle).
Geometry that may have potential for a labyrinth (and might attract UFOs).
Rod ... ...

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Re: Paradise Trinity Day
Re: "42b" design*
"... or not 2b"
Concentric salience (aka "Patterns rule!").
* added to http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod
"... or not 2b"
Concentric salience (aka "Patterns rule!").
* added to http://aitnaru.org/images/Yin_Yang_Pi.pdf
Rod

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Re: Paradise Trinity Day
Re: "Pi Shells" design
"The only game in town."
A Sunday night dashed doodle
where diameters increase by 2/sqrt(Pi).
Diameters of the two small circles:
top = sqrt(Pi)/2, bottom = sqrt(Pi)/4
About reference to "dashed doodle"
... to some, a coded riddle (tune).
Rod
"The only game in town."
A Sunday night dashed doodle
where diameters increase by 2/sqrt(Pi).
Diameters of the two small circles:
top = sqrt(Pi)/2, bottom = sqrt(Pi)/4
About reference to "dashed doodle"
... to some, a coded riddle (tune).
Rod